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2 years ago

What is the slope of a line perpendicular to y=-x?

Mathematics

2 answers:

drek231 [11]2 years ago

8 0

<h3>Answer: C) 4/7</h3>

Explanation:

The given equation is in the form y = mx+b with slope m = -7/4

Take the negative reciprocal of this to get 4/7. We simply flip the fraction and the sign (from negative to positive).

Note that multiplying any original slope with its perpendicular counterpart, will always get you -1

(-7/4)*(4/7) = -1

This applies to lines that are not vertical and not horizontal.

Rom4ik [11]2 years ago

5 0

Answer:

Step-by-step explanation:

The slope of the given line is -7/4

Let the slope we want be m :

Then m * -7/4 = -1 ( as the slopes of perpendicular lines have a product of -1)

m = -1 / -7/4

= 1 * 4/7

= 4/7.

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What number divided by 2 3 4 5 6 has a remainder of 1 but when divided by 7 has no remainder?

Afina-wow [57]

301

We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...

However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.

Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).

301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.

Hope this all makes sense.

3 0

3 years ago

Please help asap!!!

sp2606 [1]

Answer:

$y=\frac{1}{6} (x+5)^2-4.5$

$y=\frac{-1}{20} (x-10)^2+1$

Step-by-step explanation:

focus at (-5, -3), and directrix y = -6

Directrix y=-6 so its a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

(h,k) is the center

P is the distance between focus and vertex

distance between focus and directrix = 2p

distance between -3 and y=-6 is 3

2p = 3

p = 3/2 or p = 1.5

Focus is (h, k+p)

given focus is (-5, -3) so h= -5 and k+p = -3

k+p=-3, plug in 1.5 for p

k + 1.5 = -3

subtract 1.5 on both sides

k = -4.5

(x-h)^2 = 4p(y-k)

$(x+5)^2= 4(1.5) (y+4.5)$

$(x+5)^2= 6(y+4.5)$

divide by 6 on both sides

then subtract 4.5 on both sides

$y=\frac{1}{6} (x+5)^2-4.5$

focus at (10, -4), and directrix y = 6.

Directrix y=6 so its a vertical parabola

so equation is

(x-h)^2 = 4p(y-k)

distance between focus and directrix = 2p

distance between -4 and y=6 is -4-6=-10

2p = -10

p = -5

Focus is (h, k+p)

given focus is (10, -4) so h= 10 and k+p = -4

k+p=-4, plug in 5 for p

k - 5 = -4

add 5 on both sides

k = 1

(x-h)^2 = 4p(y-k)

$(x-10)^2= 4(-5) (y-1)$

$(x-10)^2= -20(y-1)$

divide by -20 on both sides and add 1 on both sides

$y=\frac{-1}{20} (x-10)^2+1$

8 0

3 years ago

Pls help ASAP I DONT have time

Law Incorporation [45]

Download Symbolab it will answer your question super quick in 2 seconds

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What do all quadrilaterals have in common

Sophie [7]

All<span> of them </span>have <span>four sides, are coplanar, </span>have<span> two diagonals, and the sum of their four interior angles equals 360 degrees.</span>

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Luke is swimming in still water at a constant speed of 3 meters/second.

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Answer:

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Step-by-step explanation:

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