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Phoenix [80]
3 years ago
5

How to do this problem and the answer

Mathematics
2 answers:
NISA [10]3 years ago
5 0
Hello,

The center angle (AOL) is 80° and the inscript angle (ANL) is the half: 80°/2=40°
 
irga5000 [103]3 years ago
4 0
Use a protractor to do the problem, but try finding th answer yourself
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1 1/5 divided by 3/10
MissTica

Answer: <em><u>4.</u></em> This is because 1 and 1/5 = 1.2 and 3/10 = 0.3 and 1.2 divided by 0.3 = 4. That's because 1.2 can be split into 4 equal groups and each group has 0.3.

4 0
3 years ago
The lines below are perpendicular. If the slope of the green line is 3/2, what is the slope of the red line​?
SSSSS [86.1K]

Answer:

-2/3

Step-by-step explanation:

Perpendicular slopes have lines that multiply to -1

m* 3/2 = -1

Multiply each side by 2/3

m* 3/2 * 2/3 = -1 * 2/3

m = -2/3

The slope of the perpendicular line is -2/3

4 0
3 years ago
Read 2 more answers
Solve for x. week 13 test
Whitepunk [10]

Answer: x equals 174

Step-by-step explanation: This looks like a parallelogram and if it is then the side opposite 157 would also be 157 so u just had to add 17 to 157 and thats ur answer of 174.

3 0
3 years ago
Read 2 more answers
A golfer hits a ball from a starting elevation of 2 feet with a velocity of 70 feet per second down to a green with an elevation
ikadub [295]

Answer:

4.50 s

Step-by-step explanation:

The motion of the ball is represented by the following equation:

h(t) = 2+70t-16t^2 (1)

where

h(t) is the elevation at time t

2 ft is the initial elevation at t = 0

+70 ft/s is the initial vertical velocity

-32 ft/s^2 is the acceleration due to gravity

The green is located at an elevation of -7 feet, so the ball lands on the green when

h(t) = -7

Substituting into (1)

-7=2+70t-16t^2

And re-arranging we get

16t^2-70t-9=0

This is a second-order equation in the form

at^2+bt+c=0

which has solutions

t_{1,2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a} (2)

Here we have:

a = 16

b = -70

c = -9

Substituting into (2) we find the solutions:

t_{1,2}=\frac{70\pm \sqrt{(-70)^2-4(16)(-9)}}{2(16)}

The two solutions are:

t = 4.50 s

t = -0.125 s

The second solution is negative, and since negative time has no physical meaning, the only correct solution is

t = 4.50 s

5 0
3 years ago
Write the polynomial as a product: p^2q+r^2–pqr–pr<br> Thanks so much! Love you all who help!
Anarel [89]
Factor the equation so... 
(r^2-pr) and (p^2q-pqr)

Factor out (r^2-pr) = r(r-p)
Factor out (p^2q-pqr) = pq(p-r)

Add a negative to r(r-p) to make it -r(p-r)

(pq-r)(p-r) is the answer...  I'm sorry I can't explain things well, but I tried.
5 0
4 years ago
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