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KATRIN_1 [288]
3 years ago
13

What is the way to write 25 percent

Mathematics
2 answers:
zhenek [66]3 years ago
7 0
There are different ways to write 25% in a
decimal form- .25
fraction form- 1/4

Hope this helps :)
Pani-rosa [81]3 years ago
6 0
1/4 is the right answer.
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PLSS HELP ME WITH THIS
kolbaska11 [484]

Answer:

127

Step-by-step explanation:

400+1495=1895

1895/15=126.333333333

8 0
3 years ago
2 to the trird power plus 3 to third power - 3x4 - 5 to the seacond power divid by 5 plus (7x4)
zhenek [66]
I hope this helps ( there is no negatives )

5 0
3 years ago
Question 1
Ilia_Sergeevich [38]

We will see that the perimeter of the rectangle is exactly 390 ft, so the statement is true.

<h3>Is the fence enough?</h3>

For a rectangle of length L and width W, the perimeter is given by:

P = 2*(L + W).

In this case, we know that:

L = 120 ft

W = 75 ft

Replacing that on the perimeter equation we get:

P = 2*(120 ft + 75  ft) = 390 ft

So the perimeter is exactly 390 ft, meaning that to put a fence around the parking lot the company will need at least 390 ft of fence.

So the statement is correct.

If you want to learn more about perimeters, you can read:

brainly.com/question/24571594

4 0
2 years ago
Can we obtain a diagonal matrix by multiplying two non-diagonal matrices? give an example
polet [3.4K]
Yes, we can obtain a diagonal matrix by multiplying two non diagonal matrix.

Consider the matrix multiplication below

\left[\begin{array}{cc}a&b\\c&d\end{array}\right]   \left[\begin{array}{cc}e&f\\g&h\end{array}\right] =  \left[\begin{array}{cc}a e+b g&a f+b h\\c e+d g&c f+d h\end{array}\right]

For the product to be a diagonal matrix,

a f + b h = 0 ⇒ a f = -b h
and c e + d g = 0 ⇒ c e = -d g

Consider the following sets of values

a=1, \ \ b=2, \ \ c=3, \ \ d = 4, \ \ e=\frac{1}{3}, \ \ f=-1, \ \ g=-\frac{1}{4}, \ \ h=\frac{1}{2}

The the matrix product becomes:

\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}\frac{1}{3}&-1\\-\frac{1}{4}&\frac{1}{2}\end{array}\right] = \left[\begin{array}{cc}\frac{1}{3}-\frac{1}{2}&-1+1\\1-1&-3+2\end{array}\right]= \left[\begin{array}{cc}-\frac{1}{6}&0\\0&-1\end{array}\right]

Thus, as can be seen we can obtain a diagonal matrix that is a product of non diagonal matrices.
8 0
3 years ago
Read 2 more answers
Since the normal curve is not symmetrical the area corresponding to a z-score of +1.0 will be different from that corresponding
Kazeer [188]
True or false i think true
7 0
3 years ago
Read 2 more answers
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