Ask question

Ask question

All categories

3 years ago

12

Please help me solve for x (show work) -4/7x = -1

2 answers:

Aliun [14]3 years ago

5 0

<h2>See the attachment✔</h2>

...... ❤

Law Incorporation [45]3 years ago

3 0

$\frac{ - 4}{ \: \: 7} x = - 1$

Now firstly we have to take 7 to right hand side and multiply -1 by 7

$- 4x = - 1 \times 7$

$- 4x = - 7$

Now we have to take -4 to the right hand side and divide -7 by -4

$x = \frac{ - 7}{ - 4}$

As we know that in case of division - and - are cancelled so ,

$x = \frac{7}{4}$

Hope it helps u mate

You might be interested in

Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

7 0

3 years ago

How do u write (2b)^4 without exponents

bearhunter [10]

Since you don't know the value of b about the best that you could do is:

(2b)^4

16b^4

16b*b*b*b

4 0

3 years ago

Read 2 more answers

On the first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75. The school took in $6

denis-greek [22]

<u>ANSWER:</u>

The price of senior citizen ticket is $4 and price of child ticket is $7.

<u>SOLUTION: </u>

Given, first day of sales the school sold 3 senior citizen tickets and 9 child tickets for a total of $75.

The school took in $67 on the second day by selling 8 senior citizen tickets and 5 child tickets.

We need to find what is the price each of one senior citizen tickets and one child tickets.

Let, the price of senior citizen ticket be "x" and price of child ticket be "y"

Then according to the given information,

3x + 9y = 75

x + 3y = 25 [by cancelling the common term 3.

x = 25 – 3y ---- (1)

And, 8x + 5y = 67 ---- (2)

Substitute (1) in (2)

8(25 – 3y) + 5y = 67

200 – 24y + 5y = 67

5y – 24y = 67 – 200

-19y = -133

y = $\frac{133}{19}$

y = 7

Now substitute y value in (1)

x = 25 – 3(7)

x = 25 – 21 = 4

Hence, the price of senior citizen ticket is $4 and price of child ticket is $7.

4 0

3 years ago

If a^2+3a+9=0, What is a^3?

kifflom [539]

i dunooo i dont even nooooo

7 0

3 years ago

A meteorologist in denver recorded y = the number of days of rain during a 30-day period. does y have a binomial distribution? i

olga_2 [115]

Solution: Yes, the random variable y will have a binomial distribution. Because there are two possible outcomes 1. number of days of rain and 2. number of days of no rain.

The parameters of binomial distribution are $n$ and $p$

The parameter n is given as the number of day's under consideration.

$\therefore n=30$

The parameter p is not given, but it can be estimated by number of days it rained divided by the total number of days under consideration.

$\therefore p=\frac{y}{n} =\frac{y}{30}$

3 0

3 years ago