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3 years ago

Please help me solve for x (show work) -4/7x = -1

Mathematics

2 answers:

Aliun [14]3 years ago

5 0

<h2>See the attachment✔</h2>

...... ❤

Law Incorporation [45]3 years ago

3 0

$\frac{ - 4}{ \: \: 7} x = - 1$

Now firstly we have to take 7 to right hand side and multiply -1 by 7

$- 4x = - 1 \times 7$

$- 4x = - 7$

Now we have to take -4 to the right hand side and divide -7 by -4

$x = \frac{ - 7}{ - 4}$

As we know that in case of division - and - are cancelled so ,

$x = \frac{7}{4}$

Hope it helps u mate

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Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago

Which mixed number is equivalent to 708/100

Brut [27]

Hello there!

The correct answer is 7 $\frac{8}{100}$ .

Hope This Helps You!
Good Luck :)

3 0

2 years ago

Pls answer ASAP

ololo11 [35]

The rephrased statement for Kun's proof is: A. In quadrilateral ABCD, if AB ≅ DC & AD ≅ BC, then AB║DC & AD║BC.

<h3>What is a Parallelogram?</h3>

A parallelogram is a quadrilateral that has two opposite sides that are congruent to each other and are also parallel to each other.

This means that if two pairs of opposite sides of a quadrilateral are congruent and parallel, then it is a parallelogram.

Rephrasing Kun's statement in his proof will therefore be: A. In quadrilateral ABCD, if AB ≅ DC & AD ≅ BC, then AB║DC & AD║BC.

Learn more about a parallelogram on:

brainly.com/question/12167853

#SPJ1

8 0

1 year ago

Divide. (-5w^10+10w^8+5w^6)/(5w^5)

Veronika [31]

<span>(-5w^10+10w^8+5w^6)/(5w^5)
to divide we can factor out 5w^5 from the numerator
=[5w^5(-w^5+2w^3+w)]/(5w^5)
5w^5 will cancel out to have
=(-w^5+2w^3+w)
Hence
Answer:</span>(-w^5+2w^3+w)<span>

</span>

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3 years ago

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Reika [66]

Answer:

could you show a picture and repost thx

Step-by-step explanation:

7 0

2 years ago