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Virty [35]
3 years ago
9

what is the equation of the line described below written in slope-intercept form? the line passing through point (2,2) and perpe

ndicular to the line whose equation is y = x
Mathematics
1 answer:
djverab [1.8K]3 years ago
5 0

Answer:

The equation of line passing through point (2 , 2) and perpendicular to line y = x is  y = - x + 4   .

Step-by-step explanation:

Given as :

The line equation is y = x

Now, equation of line in slope-intercept form y = m x + c

where m is the slope of line and c is y-intercept

Comparing given line equation with standard line equation

The slope of line y = x is m = 1

Again

Other line is passing through point (2 ,2) and is perpendicular to line y = x

Let The slope of other line = M

∵ From perpendicular lines property

Product of slope of lines = - 1

i.e m × M = - 1

Or , M = \dfrac{ - 1}{m}

Or, M = \dfrac{ - 1}{1}

∴  M = - 1

<u>Now, Equation of other line in point-slope form</u>

The other line is passing through point (2 , 2) and slope M = - 1

So, y - y_1 = M × (x - x_1)

Or, y - 2 = - 1 × ( x - 2 )

Or, y - 2 = - x + 2

Or, y = - x + 2 + 2

Or, y = - x + 4

Hence, The equation of line passing through point (2 , 2) and perpendicular to line y = x is  y = - x + 4   . Answer

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