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ale4655 [162]
3 years ago
7

Sally borrows some money at a 15% interest rate. She repays the loan in full after 30 months and pays $1692 in interest. How muc

h did she borrow?
Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Answer: $4512 was the amount she borrowed.

Step-by-step explanation:

SI = 1692

R = 15% = 0.15

T = 30 months = 2.5 years

SI = PRT

1692 = P x 0.15 x 2.5

1692 = 0.375P

P = 1692 / 0.375

P = 4512

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The area under the curve associated with a z score of 3 is
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Assuming you're looking for a left-tail area,

\mathbb P(Z

or, if you meant right-tail,

\mathbb P(Z>3)\approx0.0013
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3 years ago
Find the equation of the line in y=mx+b form with slope 3 that passes through the point (5,19)
Kipish [7]
Point slope form:
we need a point (x₀,y₀) and the slope (m).
y-y₀=m(x-x₀)

In this case:
 m=3
(5,19)

y-19=3(x-5)
y-19=3x-15
y=3x-15+19
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3 years ago
The test to detect the presence of a liver disorder is 98% accurate for a person who has the disease and 97% accurate for a pers
vladimir1956 [14]
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7 0
3 years ago
Read 2 more answers
Can please cross multiply this for me :)
Alchen [17]
64 x 100 = 6400
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4 0
4 years ago
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The following six independent length measurements were made (in feet) for a line: 736.352, 736.363, 736.375, 736.324, 736.358, a
horrorfan [7]

Answer:

Assuming population data

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

s = \sqrt{0.000425}=0.0206

Step-by-step explanation:

For this case we have the following data given:

736.352, 736.363, 736.375, 736.324, 736.358, and 736.383.

The first step in order to calculate the standard deviation is calculate the mean.

Assuming population data

\mu = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\mu = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

\sigma^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6}

And we got \sigma^2 =0.000354

And the deviation would be just the square root of the variance:

\sigma = \sqrt{0.000354}=0.0188

Assuming sample data

\bar X = \frac{\sum_{i=1}^6 X_i}{6}

The value for the mean would be:

\bar X = \frac{736.352+736.363+736.375+736.324+736.358+736.383}{6}=736.359

And the population variance would be given by:

s^2 = \frac{\sum_{i=1}^6 (x_i-\bar x)}{6-1}

And we got s^2 =0.000425

And the deviation would be just the square root of the variance:

s = \sqrt{0.000425}=0.0206

6 0
3 years ago
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