Vertex at the origin and opening down → y=ax^2
Width: w=16
x=w/2→x=16/2→x=8
x=8, y=-16→y=ax^2→-16=a(8)^2→-16=a(64)→-16/64=a(64)/64→-1/4=a→a=-1/4
y=ax^2→y=-(1/4)x^2
7 m from the edge of the tunnel → x=w/2-7=8 m-7 m→x=1 m
x=1→y=-(1/4)x^2=-(1/4)(1)^2=-(1/4)(1)→y=-1/4
Vertical clearance: 16-1/4=16-0.25→Vertical clearance=15.75 m
Please, see the attached file.
Answer: Third option 15.75 m
Answer:
Option D.

Step-by-step explanation:
The area of the circular bases is:

Where
is the radius of the circle
Then


The area of the rectangle is:

Where

b is the width of the rectangle and
is the length
Then the area of the rectangle is:


Finally the total area is:


18/30 simplifies into 6/10 which then is put in decimal form of 0.6