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ale4655 [162]
3 years ago
7

Sally borrows some money at a 15% interest rate. She repays the loan in full after 30 months and pays $1692 in interest. How muc

h did she borrow?
Mathematics
1 answer:
Tanya [424]3 years ago
3 0

Answer: $4512 was the amount she borrowed.

Step-by-step explanation:

SI = 1692

R = 15% = 0.15

T = 30 months = 2.5 years

SI = PRT

1692 = P x 0.15 x 2.5

1692 = 0.375P

P = 1692 / 0.375

P = 4512

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11111nata11111 [884]

Answer:

100

Step-by-step explanation:

they are vertical angles therefore, they have the same measure.

4 0
3 years ago
Compare and contrast the radius, and the diameter of a circle. How are they alike? How are they different?
Furkat [3]
You should take into account that the radius is half the diameter and the diameter is the length from the side to side of a circle.
5 0
2 years ago
-20x2 + x + 12<br> Factor
Pavel [41]

Answer:

[x-3] [x+4]

Step-by-step explanation:

You look to see if you spot the appropriate factors strait away. If you can not immediately determine them you have to consider all of the potential ones and reason out which ones work.

7 0
3 years ago
Triangle RST has sides measuring 22 inches and 13 inches and a perimeter of 50 inches. What is the area of triangle RST? Round t
VladimirAG [237]

Using the Heron's formula, the area of the triangle is: D. 95 square inches.

<h3>What is the Heron's Formula?</h3>

Area = √[s(s - a)(s - b)(s - c)] where s is half the perimeter, or (a + b + c)/2.

Given the following:

s = semi-perimeter = 1/2(50) = 25 in.

a = length of side a = 22 in.

b = length of side b = 13 in.

c = length of side c = 50 - 22 - 13 = 15 in.

Plug in the values

Area = √[25(25 - 22)(25 - 13)(25 - 15)]

Area = √[25(3)(12)(10)]

Area ≈ 95 square inches.

Learn more about the Heron's formula on:

brainly.com/question/10713495

#SPJ1

5 0
2 years ago
Solve the system 6x -2y+z= -2 2x+ 3y - 3z =11 x+ 6y=31
weqwewe [10]

Answer:

x = 1

y = 5

z = 2

Step-by-step explanation:

System of equations:

6x - 2y + z = -2

2x + 3y - 3z = 11

x + 6y = 31

Isolate one variable in any of the equations:

x + 6y = 31

x = 31 - 6y

Plug in this value for x in another equation:

6(31 - 6y) - 2y + z = -2

186 - 36y - 2y + z = -2

186 - 38y + z = -2

-38y + z = -188

z = -188 + 38y

Plug in these values in the remaining equation:

2(31 - 6y) + 3y - 3(-188 + 38y) = 11

62 - 12y + 3y + 564 - 114y = 11

626 - 12y + 3y - 114y = 11

626 - 9y - 114y = 11

626 - 123y = 11

-123y = -615

y = 5

Plug in value of y into our other answers to solve for x and z:

x = 31 - 6(5)

x = 31 - 30

x = 1

z = -188 + 38(5)

z = -188 + 190

z = 2

Check your work:

6x - 2y + z = -2

6(1) - 2(5) + 2 = -2

6 - 10 + 2 = -2

-4 + 2 = -2

-2 = -2

Correct!

*Note there are several ways to solve for these types of problems. I used substitution*

8 0
2 years ago
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