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bulgar [2K]
3 years ago
11

Which sets of mRNA codons could genetically code for a protein with the following amino acid composition:

Biology
2 answers:
Jobisdone [24]3 years ago
4 0

Ans.

Codons are three nucleotide sequences present on DNA or RNA that codes for the amino acids or provide stop signal at the time of protein synthesis. Each codon codes for a specific amino acid. The amino acid proline (pro) is coded by CCG, CCT, CCA, and CCC; aspartate (asp) is coded by GAT and GAC; glycine is coded by GGA, GGG, GGT, and GGC; and lysine is coded by AAA and AAG.

Thus, the correct answer is 'option D). CCA-GAC-GGC-AAA.'

Semenov [28]3 years ago
3 0
I think is D)... sorry if you get it wrong but is the one that make more sense
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14. Pat and Tracy each have a sibling who has the recessive trait of sickle cell disorder. Neither Pat. Tracy or
Nady [450]

Answer:

Since sickle cell disease is a disorder with an autosomal dominant inheritance pattern, and in light of the lack of data, it could be said that the only way for Pat and Tracy to have a child with sickle cell disease is for both of them to be healthy carriers of the gene, with a 25% probability.

Explanation:

Considering that both Pat and Tracy each have a sibling with a sickle cell trait and that both they and their parents are healthy, it must be assumed that some of their parents are healthy carriers:

  1. Pat and Tracy do not have sickle cell trait. In this case, there is no chance that they will have a child with sickle cell disease.
  2. Either Pat or Tracy has the trait, but the other does not. It is possible that at least one of their children is a healthy carrier.
  3. If both Tracy and Pat have sickle cell trait, the chances of having a child with sickle cell disease are:

Alelles       R         r

R              RR       Rr

r               Rr        rr

RR: healthy (25%).

Rr:  healthy carrier (50%).

rr: sickle cell disease (25%).

<em>If Pat and Tracy are healthy carriers of the gene that determines sickle cell disease, the chance of having a child with the disease is 25%</em>.

Learn more:

Autosomal recesive inheritance brainly.com/question/10605612

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D NAD is used to directly break apart the glucose molecules I believe
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Thus, oviduct is the answer

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