Find average rate of change f(x)=x^(2)-3x-4 ; [-1,3]

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3 0

$\bf slope = m = \cfrac{rise}{run} \implies \cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby \begin{array}{llll} average~rate\\ of~change \end{array}\\\\[-0.35em] \rule{34em}{0.25pt}\\\\ f(x)= x^2-3x-4\qquad \begin{cases} x_1=-1\\ x_2=3 \end{cases}\implies \cfrac{f(3)-f(-1)}{3-(-1)} \\\\\\ \cfrac{[(3)^2-3(3)-4]~~-~~[(-1)^2-3(-1)-4]}{3+1} \\\\\\ \cfrac{[-4]~~-~~[1+3-4]}{4}\implies \cfrac{[-4]-[0]}{4}\implies -1$

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marshall27 [118]

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The upper-left coordinates on a rectangle are (-5, 6)(−5,6)left parenthesis, minus, 5, comma, 6, right parenthesis, and the uppe

sammy [17]

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

The upper-left coordinates on a rectangle are (−5,6) and the upper-right coordinates are (−2,6). The rectangle has a perimeter of 16units. Draw the rectangle on the coordinate plane below.

If the coordinates of the top of the triangle (breadth) is (−5,6) and (−2,6), we can calculate the breadth of the rectangle by taking the difference between the two points using the formula:

D = √(y₂-y₁)²+(x₂-x₁)²

Given x₁ = -5, y₁= 6, x₂ = -2 and y₂ = 6

D = √(6-6)²+(-2-(-5))²

D = √0²+3²

D = √9

D = 3 units

Breadth = 3 units

Given the Perimeter to be 16 units and the formula for calculating the perimeter of rectangle t be P = 2(L+B), we can get the length of the rectangle.

16 = 2(3+L)

16 = 6+2L

16-6 = 2L

2L = 10

L = 10/2

L = 5 units.

Hence the length of the rectangle is 5 units and the breadth is 3 units. Find the diagram in the attachment.