1/8 divide both numbers by 5
<span>Winning Probablity = 0.2, hence Losing Probability = 0.8
Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0)
Winning once W1 is equal to L4, winning zero times is losing 5 times.
p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5);
p (W1) + p(W0) = p(L4) + p(L5)
p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5
p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>
Answer:
6 units
Step-by-step explanation:
HOPE THIS HELPED
Answer:
(-7, -10)
Step-by-step explanation:
Solve for x and y in double variable equation
y = 2x + 4
y = x - 3
y = x - 3, plug in to first equation
x - 3 = 2x + 4
x = -7
y = -7 - 3
y = -10
(-7, -10)
Answer
yes
Step-by-step explanation:
Because yes
