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3 years ago

5

What is 9x+35= -5y in slope intercept form, and what is the slope and y-intercept.

2 answers:

Pie3 years ago

6 0

Answer:

y = -9/5x - 7

Step-by-step explanation:

slope is -9/5 and y intercept is -7

alexdok [17]3 years ago

4 0

Answer:

Slope Intercept Form: -(9/5)x-7=y

Slope: -9/5

Y intercept: -7

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Convert the decimal number 183 into an equivalent 32 bit binary number. show all your work.

german

The bits are determined by repeated division by 2 to yield either 0 or 1.

183/2 = 91 rem 1 => 1 (lowest bit) 2⁰
91/2 = 45 rem 1 => 1 (next higher bit) 2¹
45/2 = 22 rem 1 => 1 (next higher bit) 2²
22/2 = 11 rem 0 => 0 (next highrt bit) 2³
11/2 = 5 rem 1 => 1 (next higher bit) 2⁴
5/2 = 2 rem 1 => 1 (next higher bit) 2⁵
2/2 = 1 rem 0 => 0 (next higher bit) 2⁶
1/2 = 0 rem 1 => 1 (next higher bit) 2⁷
The next higher 24 bits have 0 in each bit.

For 32-bit system,
183 = 00000000 00000000 00000000 10110111 (with a space between bytes for readability)

Answer: 00000000000000000000000010110111

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3 years ago

Someone help me with this question please I don’t know

ra1l [238]

The magic of the internet will help!

6 0

3 years ago

Write an exponential function represented by the table

Alinara [238K]

Answer:

50y= -2248283

Step-by-step explanation:

used photo math

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2 years ago

Which pair of funtions is not a pair of inverse functions? please help!!

antiseptic1488 [7]

Answer:

$f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Step-by-step explanation:

we know that

To find the inverse of a function, exchange variables x for y and y for x. Then clear the y-variable to get the inverse function.

we will proceed to verify each case to determine the solution of the problem

<u>case A)</u> $f(x)=\frac{x+1}{6} , g(x)=6x-1$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y+1}{6}$

Isolate the variable y

$6x=y+1$

$y=6x-1$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=6x-1$

therefore

f(x) and g(x) are inverse functions

<u>case B)</u> $f(x)=\frac{x-4}{19} , g(x)=19x+4$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y-4}{19}$

Isolate the variable y

$19x=y-4$

$y=19x+4$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=19x+4$

therefore

f(x) and g(x) are inverse functions

<u>case C)</u> $f(x)=x^{5}, g(x)=\sqrt[5]{x}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=y^{5}$

Isolate the variable y

fifth root both members

$y=\sqrt[5]{x}$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=\sqrt[5]{x}$

therefore

f(x) and g(x) are inverse functions

<u>case D)</u> $f(x)=\frac{x}{x+20} , g(x)=\frac{20x}{x-1}$

Find the inverse of f(x)

Let

y=f(x)

Exchange variables x for y and y for x

$x=\frac{y}{y+20}$

Isolate the variable y

$x(y+20)=y$

$xy+20x=y$

$y-xy=20x$

$y(1-x)=20x$

$y=20x/(1-x)$

Let

$f^{-1}(x)=y$

$f^{-1}(x)=20x/(1-x)$

$\frac{20x}{1-x}\neq \frac{20x}{x-1}$

therefore

f(x) and g(x) is not a pair of inverse functions

7 0

3 years ago

Read 2 more answers

Hello please help will give brainliest!

jeka57 [31]

The answer is A. because the first part shows the ratio 3:2 and the other 2 shows equivalent ratios.

8 0

3 years ago