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4 years ago

What is P= I^2r when solving for I?

Mathematics

1 answer:

Tpy6a [65]4 years ago

8 0

Answer:

$I=\sqrt{\dfrac{P}{r}}$

Step-by-step explanation:

Divide by r and take the square root.

$P=I^2r\\\\\dfrac{P}{r}=I^2\\\\\boxed{I=\sqrt{\dfrac{P}{r}}}$

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What is the inverse of y=2x+7

Katyanochek1 [597]

Y=(0,7)
Root: (-7/2,0)

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3 years ago

6x + 4y=10 12x + y= -29

Olin [163]

Answer: x=-3 y=7.

Step-by-step explanation:

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2 years ago

What are the solutions to 7x2−15x−18=0?

Harlamova29_29 [7]

Answer:

C.) X=3 and X=-6/7

Step-by-step explanation:

Use the quadratic formula to solve

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3 years ago

Read 2 more answers

A motorcycle can travel 60 miles per gallon. Approximately how many gallons of fuel will the motorcycle need to travel 40 km?

Semenov [28]

The first thing to note is since one gallon= 60 miles then 1/2 gallon= 30 miles, now I know 1/2 is not an answer but it is easiest to decrease in moderate amounts. 1/2 gallon= 48 Km so we are close, and 1/2=0.5 so if we brought it down to 0.42 we would have 25.2 miles and 25.2 miles = 40.32. The question wants to know the approximate number and 40.32 is the closest we are going to get so the answer is 0.42

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3 years ago

Use the definition mtan=lim

Leokris [45]

(a) mtan refers to the slope of the tangent line. Given f(x) = 9 + 7x ², compute the difference quotient:

$\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h$

Then as h approaches 0 - bearing in mind that we're specifically considering h near 0, and not h = 0 - we can eliminate the factor of h in the numerator and denominator, so that

$m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x$

and so the slope of the line at P (0, 9), for which we take x = 0, is 0.

(b) The equation of the tangent line is then y = 9.

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3 years ago

What is P= I^2r when solving for I?​

What is P= I^2r when solving for I?