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KonstantinChe [14]
2 years ago
5

Use the definition mtan=lim

Mathematics
1 answer:
Leokris [45]2 years ago
4 0

(a) mtan refers to the slope of the tangent line. Given <em>f(x)</em> = 9 + 7<em>x</em> ², compute the difference quotient:

\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h

Then as <em>h</em> approaches 0 - bearing in mind that we're specifically considering <em>h</em> <em>near</em> 0, and not <em>h</em> = 0 - we can eliminate the factor of <em>h</em> in the numerator and denominator, so that

m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x

and so the slope of the line at <em>P</em> (0, 9), for which we take <em>x</em> = 0, is 0.

(b) The equation of the tangent line is then <em>y</em> = 9.

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Graph the system of equations on graph paper to answer the question. Y=2/5x+4 and y=2x+12 what is the solution for this system o
riadik2000 [5.3K]

Answer:

Solution of the given equations is (-5,2)

Step-by-step explanation:

We have been given the following system of equations:

y = (2/5)x + 4

y = 2x + 12

The solution of the system of equation can be found by finding the point of intersection of both lines on the graph. The graph of both equations is attached below.

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2 years ago
A bookmark is shaped like a rectangle with a semicircle attached at both ends. The rectangle is 17 cm
maria [59]

Answer:

80.56

Step-by-step explanation:

To find the rectangle area you just multiply its length by its width:

17 * 4 = 68

You have to sum two semicircles on top of that. Since it is 2 semicircles you can just calculate one circle. Using the circle area formula:  \pi*r^2

Since the radius (r) is 2 and \pi is 3.14, you have the following equation:

A = 3.14 * 2² ==>      A = 3.14 * 4   ==>   A = 12.56     <em>(A is Area)</em>

Sum the rectangle's area with the circle's area:

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3 years ago
Y = –8x + 8<br> y = –8x + 8
fiasKO [112]

Answer:

x=0

y=8

Step-by-step explanation:

This is a simultaneous equation

So let's solve

y=-8x+8..(1)

y=-8x+8...(2)

Add (1) and (2)

2y=16

Make y the subject of formula by dividing both sides by 2

y=8

Substitute the value for y into (2)

8=-8x+8

Collect like terms

8-8=-8x

0=-8x

Divide both sides by-8

x=0

Therefore x is 0 and y is 8

5 0
3 years ago
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