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KonstantinChe [14]
2 years ago
5

Use the definition mtan=lim

Mathematics
1 answer:
Leokris [45]2 years ago
4 0

(a) mtan refers to the slope of the tangent line. Given <em>f(x)</em> = 9 + 7<em>x</em> ², compute the difference quotient:

\dfrac{f(x+h)-f(x)}h = \dfrac{(9+7(x+h)^2)-(9+7x^2)}h = \dfrac{(9+7x^2+14xh+7h^2)-9-7x^2}h = \dfrac{14xh+7h^2}h

Then as <em>h</em> approaches 0 - bearing in mind that we're specifically considering <em>h</em> <em>near</em> 0, and not <em>h</em> = 0 - we can eliminate the factor of <em>h</em> in the numerator and denominator, so that

m_{\rm tan} = \displaystyle \lim_{h\to0}\frac{f(x+h)-f(x)}h = \lim_{h\to0}\frac{14xh+7h^2}h = \lim_{h\to0}(14x+7h) = 14x

and so the slope of the line at <em>P</em> (0, 9), for which we take <em>x</em> = 0, is 0.

(b) The equation of the tangent line is then <em>y</em> = 9.

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If m∠NOP = 24 and m∠NOQ = 110, what is m∠POQ? Angle N O Q divided into two unequal angles by ray O P. A. 62 B. 86 C. 134 D. 156
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Answer:

<em>B. 86 degrees</em>

Step-by-step explanation:

Given the following angles:

m∠NOQ = 110

m∠NOP = 24

Using the addition postulate:

m∠NOQ =  m∠NOP + m∠POQ

110 = 24 + m∠POQ

m∠POQ = 110 - 24

m∠POQ = 86

<em>Hence the measure of m∠POQ is 86 degrees</em>

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We'll use the following log rules

  • Log rule 1:  log(xy) = log(x)+log(y)
  • Log rule 2: log(x/y) = log(x)-log(y)
  • Log rule 3: log(x^y) = y*log(x)

================================================

Part 1

<h3>Answer: 2a + 2c</h3>

-------------

Work Shown:

Ln(100) = Ln(4*25)

Ln(100) = Ln(2*2*5*5)

Ln(100) = Ln(2)+Ln(2)+Ln(5)+Ln(5) ... using log rule 1

Ln(100) = a+a+c+c

Ln(100) = 2a + 2c

================================================

Part 2

<h3>Answer: 2a + b - c</h3>

-------------

Work Shown:

Ln(2.4) = Ln(24/10)

Ln(2.4) = Ln[ (2*2*2*3)/(2*5) ]

Ln(2.4) = Ln[ (2*2*3)/5 ]

Ln(2.4) = Ln(2*2*3) - Ln(5) ... using log rule 2

Ln(2.4) = Ln(2)+Ln(2)+Ln(3) - Ln(5) .... using log rule 1

Ln(2.4) = a+a+b-c

Ln(2.4) = 2a+b-c

================================================

Part 3

<h3>Answer: -3a + b - 3c</h3>

-------------

Work Shown:

Ln(0.003) = Ln(3/1000)

Ln(0.003) = Ln[ 3/( 10^3) ]

Ln(0.003) = Ln(3) - Ln(10^3) ... log rule 2

Ln(0.003) = Ln(3) - 3*Ln(10) ... log rule 3

Ln(0.003) = Ln(3) - 3*Ln(2*5)

Ln(0.003) = Ln(3) - 3*( Ln(2) + Ln(5) ) ... log rule 1

Ln(0.003) = b - 3*( a + c )

Ln(0.003) = b - 3a - 3c

Ln(0.003) = -3a + b - 3c

================================================

Part 4

<h3>Answer: 3a + 3b + 2c</h3>

-------------

Work Shown:

All logs shown for this part are in base 2

log(5400) = log(54*100)

log(5400) = log(6*9*4*25)

log(5400) = log(2*3*3*3*2*2*5*5)

log(5400) = log(2^3*3^3*5^2)

log(5400) = log(2^3)+log(3^3)+log(5^2) ... log rule 1

log(5400) = 3*log(2)+3*log(3)+2*log(5) ... log rule 3

log(5400) = 3a + 3b + 2c

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