Upon slight rearranging:
5xy-15y-40x+120, now factor 1st and 2nd pair of terms
5y(x-3)-40(x-3) which is equal to:
(5y-40)(x-3) if we factor the first parenthetical term as well
5(y-8)(x-3)
So (y-8) is a factor
Answer:
0, 3 , 8
Step-by-step explanation:
substitute n = 1, 2, 3 into the pattern rule
T₁ = 1² - 1 = 1 - 1 = 0
T₂ = 2² - 1 = 4 - 1 = 3
T₃ = 3² - 1 = 9 - 1 = 8
A. x = -6
6-x-x = 18
6-2x =18
-2x = 12
x = -6
