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3 years ago

Select all numbers that are solutions to the inequality w < 1.

Mathematics

2 answers:

Nastasia [14]3 years ago

4 0

Answer:

Step-by-step explanation:

monitta3 years ago

3 0

Answer:

I know it’s going to be -5 and -1.3 but I’m not sure about the zero I don’t know if you count zeros to but please let me know.

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Determine the length and conductivity of a wire with diameter 4.2 mm constructed from an alloy of resistivity 3.2 x 10^-8 ohms-m

xz_007 [3.2K]

Answer:

1) L = 3.465 × 10^2; 31250000 S/m

2) terminal pd = 11V

3) ₦2

Step-by-step explanation:

diameter of wire (d) = 4.2mm = 4.2 × 10^-3m

resistivity 3.2 x 10^-8 ohms-meter

Resistance(R) = 0.8 ohms

Area of wire (A)= πd^2 / 4

A =[ ( 22/7) * (4.2×10^-3)^2] / 4

A = [22/7 * 17.64×10^-6] / 4

A = 13.86×10^-6m^2

Recall:

Resistivity = (R ×A) / Length

Length = (R × A) / resistivity

Length(L) = [(0.8)(13.86×10^-6)] / 3.2 x 10^-8

L = (11.088 × 10^-6) / 3.2 x 10^-8

L = 3.465 × 10^2

Conductivity = 1/resistivity

Conductivity = 1/3.2 x 10^-8

Conductivity = 31250000 S/m

Series resistor = 1.5 and 4.0 ohms

e.m.f (E) = 12V, internal resistance 'r' = 0.5

Recall :

I = E / (R + r)

Where I = current

R = circuit resistance

R = Rs = 1.5 + 4.0 (series connection) = 5.5

Recall : I = V/R

Where V = voltage ( terminal pd)

Therefore,

V/R = E/(R+r)

V/5.5 = 12/(5.5 + 0.5)

V/5.5 = 12/6

V/5.5 = 2

V = 5.5 × 2

V = 11V

3) power = 100W, t =10 hours

Energy consumed = power × time

Energy consumed = 100W × 10 hrs = 1000Whr

Recall: 1 KW = 1000 W

Therefore, energy consumed = 1KW

Cost of energy per KW = ₦2

Therefore, cost of lightning the lamp = ₦2 × 1KW = $2

4 0

4 years ago

Use the drawing tool(s) to form the correct answer on the provided graph. Graph the solution to this system of inequalities in t

Leya [2.2K]

The solution to the system of inequalities is (-3.375, 1.75)

<h3>How to graph the inequalities?</h3>

The system of inequalities is given as:

3y > 2x+12

2x+y < -5

Next, we plot the graph of the system using a graphing tool

From the graph, both inequalities intersect at

(-3.375, 1.75)

Hence, the solution to the system of inequalities is (-3.375, 1.75)

Read more about system of inequalities at:

brainly.com/question/19526736

#SPJ1

8 0

2 years ago

What is 15/16 simplafyed?

borishaifa [10]

It can not be simplified because the numerator and denominator can not be divided between the same number, so that each results an integer number.

5 0

4 years ago

A recipe calls for 1/8 teaspoon of vanilla extract if the recipe is doubled how much vanilla extract is needed

LUCKY_DIMON [66]

Answer:

2/8

Step-by-step explanation:

1. take 1/8 and multiply it by 2/1

3 0

3 years ago

Read 2 more answers

Explain the steps to finding the vertex of g(x) = 3x2 + 12x + 15

RUDIKE [14]

Answer:

The vertex of this parabola, $(-2, 3)$ , can be found by completing the square.

Step-by-step explanation:

The goal is to express this parabola in its vertex form:

$g(x) = a\, (x - h)^2 + k$ ,

where $a$ , $h$ , and $k$ are constants. Once these three constants were found, it can be concluded that the vertex of this parabola is at $(h,\, k)$ .

The vertex form can be expanded to obtain:

$\begin{aligned}g(x)&= a\, (x - h)^2 + k \\ &= a\, \left(x^2 - 2\, x\, h + h^2\right) + k = a\, x^2 - 2\, a\, h\, x + \left(a\,h^2 + k\right)\end{aligned}$ .

Compare that expression with the given equation of this parabola. The constant term, the coefficient for $x$ , and the coefficient for $x^2$ should all match accordingly. That is:

$\left\lbrace\begin{aligned}& a = 3 \\ & -2\,a\, h = 12 \\& a\, h^2 + k = 15\end{aligned}\right.$ .

The first equation implies that $a$ is equal to $3$ . Hence, replace the " $a\!$ " in the second equation with $3\!$ to eliminate $\! a$ :

$(-2\times 3)\, h = 12$ .

$h = -2$ .

Similarly, replace the " $a$ " and the " $h$ " in the third equation with $3$ and $(-2)$ , respectively:

$3 \times (-2)^2 + k = 15$ .

$k = 3$ .

Therefore, $g(x) = 3\, x^2 + 12\, x + 15$ would be equivalent to $g(x) = 3\, (x - (-2))^2 + 3$ . The vertex of this parabola would thus be:

$\begin{aligned}&(-2, \, 3)\\ &\phantom{(}\uparrow \phantom{,\,} \uparrow \phantom{)} \\ &\phantom{(}\; h \phantom{,\,} \;\;k\end{aligned}$ .

8 0

3 years ago