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AveGali [126]
3 years ago
8

What is 10/3 as a mixed number

Mathematics
2 answers:
Fudgin [204]3 years ago
7 0
<span>10/3 as a mixed number = 3 1/3
------------------------------------------------</span>
KATRIN_1 [288]3 years ago
5 0
3 and 1/3 if u have a TI-30xiiS caculater you just press 10 the abc button 3 and get ur anwser
You might be interested in
Round to the nearest tenth.
laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

<u />

<u>Recall the Law of Cosines</u>

<u />a^2=b^2+c^2-2bc\cdot cos(A)

<u>Identify angles and sides</u>

<u />m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6

<u>Solve for side "a"</u>

<u />a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2

Therefore, the length of line segment BC is about 8.2 units

8 0
2 years ago
Write without exponents (3p)^2
Brums [2.3K]
(3p)(3p) or 3p x 3p. Cause the exponent means 3p times 3p
4 0
3 years ago
Read 2 more answers
Identify the asymptotes of y=1 over x -6<br><br><br> A.<br> B.<br> C.<br> D.
Westkost [7]

Answer:

  D.  x = 0; y = -6

Step-by-step explanation:

There is a vertical asymptote at the value of x that makes the denominator zero. That value is x=0. This is sufficient to choose the correct answer.

When x gets large, the term 1/x nears zero, so the value of y nears -6. This is the horizontal asymptote.

  vertical asymptote: x = 0; horizontal asymptote: y = -6

6 0
3 years ago
I don’t understand this help please
Elodia [21]

Answer:

  9

Step-by-step explanation:

The first simplification we can make is to replace 6^0 with 1.

The first rules of exponents we can apply are ...

  <em>(a·b)^c = a^c·b^c</em> . . . . . . similar to the distributive property

<em>   (a^b)^c = a^(b·c)</em>

This reduces your expression to ...

  (2^8\cdot 3^{-5})^{-2}\cdot\left(\dfrac{3^{-2}}{2^3}\right)^4\cdot 2^{28}=2^{8(-2)}\cdot 3^{-5(-2)}\cdot\dfrac{3^{-2(4)}}{2^{3(4)}}\cdot 2^{28}\\\\=2^{-16}\cdot 3^{10}\cdot\dfrac{3^{-8}}{2^{12}}\cdot 2^{28}

Now we can apply another two rules of exponents:

<em>   (a^b)(a^c) = a^(b+c)</em>

<em>   1/a^b = a^-b</em>

Using these, we have ...

  =2^{-16-12+28}\cdot 3^{10-8}\\\\=2^0\cdot 3^2\\\\=1\cdot 9=9

The value of the expression is 9.

3 0
3 years ago
Please help me!!!!!!!!
disa [49]
X=numerator

fraction=x/16

x / 16=3/4
x=16(3/4)
x=(16*3)/4
x=12

fraction=12/16

To check:
12/16=0.75
3/4=0.75
3 0
2 years ago
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