Answer:
Test scores of 10.2 or lower are significantly low.
Test scores of 31 or higher are significantly high
Step-by-step explanation:
Z-score:
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Significantly low:
Z-scores of -2 or lower
So scores of X when Z = -2 or lower




Test scores of 10.2 or lower are significantly low.
Significantly high:
Z-scores of 2 or higher
So scores of X when Z = 2 or higher




Test scores of 31 or higher are significantly high
Answer:
1 2/3
Step-by-step explanation:
I assume that the parabola in this particular problem is one whose axis of symmetry is parallel to the y axis. The formula we're going to use in this case is (x-h)2=4p(y-k). We know variables h and k from the vertex (1,20) but p is not given. However, we can solve for p by substituting values x and y in the formula with the y-intercept:
(0-1)^2=4p(16-20)
Solving for p, p=-1/16.
Going back to the formula, we can finally solve for the x-intercepts. Simply fill in variables p, h and k then set y to zero:
(x-1)^2=4(-1/16)(0-20)
(x-1)^2=5
x-1=(+-)sqrt(5)
x=(+-)sqrt(5)+1
Here, we have two values of x
x=sqrt(5)+1 and
x=-sqrt(5)+1
thus, the answers are: (sqrt(5)+1,0) and (-sqrt(5)+1,0).
The answer is C. 50 in, 48 in, 14 in
In a right triangle, a² + b² = c², where c is the longest side (hypotenuse), a and b are the other two sides.
14² + 48² = 196 + 2304 = 2500
50² = 2500
Picture related to the question is attached below
Answer:
Kendra should have divided by 2 instead of multiplying by 2
Step-by-step explanation:
40 percent = percentage who plan to attend
100% = total percentage of student
From the question ;
When reducing percentages, division is employed and this the equation should be :
40/2 ÷ 100/2
40/2 * 2/100
20 * 1/50
20/50
= 0.4
0.4 * 50
= 20 students