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Mrac [35]
3 years ago
12

How to draw to segments with the same midpoint

Mathematics
1 answer:
prisoha [69]3 years ago
8 0
Just draw a line at the midpoint and a salon also if this helps OK
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Given the curve y=3x^5+6x^4-4x^3+1 find it's turning point and point of inflection
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Express the area of the entire rectangle. you answer should be a polynomial in standard form.
mixer [17]

Answer:x^2 + 9x + 20

Step-by-step explanation:

You could just multiply (x+4)(x+5) and get x^2 + 9x + 20, but judging from the picture, it looks like they want you to split it into 4 rectangles

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Read 2 more answers
8) through: (-3, -2), perp. to y = x – 1<br> A) y=-5x – 1 B) y=-4x – 5<br> C) y=-x – 5 D) y=-5x – 4
nexus9112 [7]

<u>Answer:</u>

The equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

<u>Solution:</u>

Given, line equation is y = x – 1 ⇒ x – y – 1 = 0. And a point is (-3, -2)

We have to find the line equation which is perpendicular to above given line and passing through the given point.

Now, let us find the slope of the given line equation.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-1}=1

We know that, <em>product of slopes of perpendicular lines is -1. </em>

So, 1 \times slope of perpendicular line =  -1

slope of perpendicular line = -1

Now let us write point slope form for our required line.

\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)

y – (-2) = -1(x – (-3))

y + 2 = -1(x + 3)

y + 2 = -x – 3

x + y + 2 + 3 = 0

x + y + 5 = 0

y = -x -5

Hence the equation through (-3, -2) and perpendicular to y = x – 1 is y = -x -5 and option c is correct.

8 0
3 years ago
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