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Julli [10]
3 years ago
12

When developing a question for a scientific inquiry, the question will ideally  A.  identify variables.  B.  be measurable.  C. 

not just simply ask why.  D.  all of these
Physics
2 answers:
Rus_ich [418]3 years ago
6 0
When developing a question for a scientific inquiry, the question will ideally D. all of these.
When it comes to a scientific inquiry, it is important that the question identify variables, be measurable, and not just simply ask why. There have to be a couple of variables, you have to be able to measure the results, and to prove them, supported by evidence.
Airida [17]3 years ago
3 0

THE ANSWER IS

all of these


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Answer:

The equivalent stiffness of the string is 8.93 N/m.

Explanation:

Given that,

Spring stiffness is

k_{1}=20\ N/m

k_{2}=30\ N/m

k_{3}=15\ N/m

k_{4}=20\ N/m

k_{5}=35\ N/m

According to figure,

k_{2} and k_{3} is in series

We need to calculate the equivalent

Using formula for series

\dfrac{1}{k}=\dfrac{1}{k_{2}}+\dfrac{1}{k_{3}}

k=\dfrac{k_{2}k_{3}}{k_{2}+k_{3}}

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k=\dfrac{30\times15}{30+15}

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k and k_{4} is in parallel

We need to calculate the k'

Using formula for parallel

k'=k+k_{4}

Put the value into the formula

k'=10+20

k'=30\ N/m

k_{1},k' and k_{5} is in series

We need to calculate the equivalent stiffness of the spring

Using formula for series

k_{eq}=\dfrac{1}{k_{1}}+\dfrac{1}{k'}+\dfrac{1}{k_{5}}

Put the value into the formula

k_{eq}=\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{35}

k_{eq}=8.93\ N/m

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Explanation:

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