H = mc∆T
where, H=heat energy
c = SHC
H = 2*921*(40-20)
H = 36840J
H = 36.84KJ
The energy transferred to it is 36.84KJ
The distance that the canoe moves in this process is 1.29 meters.
We first have to find the center of mass

Where
Ms = Woman's mass = 45
Mc = Canoe's mass = 60kg
Xs = position from left= 1 cm
Xc = position from left end of canoe's mass = 2.5cm
When we put these values into the equation we have:

The center of gravity lies at the center of this boat. Therefore,

5.00 - 1. 00 = 4 meters

To get the distance that is moved by this canoe
distance = 3.143-1.857
= 1.286
≈ 1.29 meters
The distance that the canoe moves in this process is 1.29 meters.
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To identify a satirical tone, look for words an author uses to exaggerate a particular character behavior to make that person appear ridiculous to the reader. The statement is True.
<h3>What is character?</h3>
What a person thinks upon a situation and get through it makes the character of a person and defines his behavior.
Given is a statement "To identify a satirical tone, look for words an author uses to exaggerate a particular character behavior to make that person appear ridiculous to the reader".
The words used by the person forms the character. So, the author searches for the word which says about his character but the reader finds it ridiculous.
Thus, the statement is true.
Learn more about character.
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This question is incomplete, the complete question is;
A parallel-plate capacitor is made from two aluminum-foil sheets, each 3.0 cm wide and 5.00 m long. Between the sheets is a mica strip of the same width and length that is 0.0225 mm thick. What is the maximum charge?
(The dielectric constant of mica is 5.4, and its dielectric strength is 1.00×10⁸ V/m)
Answer: the maximum charge q is 716.85 μF
Explanation:
Given data;
with = 3.0 cm = 0.03
breathe = 5.0 m
Area = 0.03 × 5 = 0.15 m²
dielectric strength E = 1.00 × 10⁸
∈₀ = 8.85 × 10⁻¹²
constant K = 5.4
maximum charge = ?
the capacitor C = KA∈₀ / d
q = cv so c = q/v
now
q/v = KA∈₀ / d
q = vKA∈₀/d = EKA∈₀
we substitute
q = (1.00 × 10⁸) × 5.4 × 0.15 × 8.85 × 10⁻¹²
q = 716.85 × 10⁻⁶ F
q = 716.85 μF
the maximum charge q is 716.85 μF