The force of attraction between two objects can be illustrated using Newton's Law of Universal Gravitation.
The relation between the different parameters is shown in the attached image.
Now, from the relation, we can deduce that the force between the two objects is directly proportional to the masses of the two objects.
This means that, if the mass of one object is doubled, then the force between the two objects will also be doubled.
Answer:
The internet is most useful to them because they use it to communicate.
Explanation:
If I were to send a message to my brother in Florida, through the internet, while I'm in Pennsylvania he would get it in minutes. On the other hand if I were going to meet him and then explain what I wanted to tell him in person it would take a much longer time.
Answer:
A 2 d vector model
The acceleration function is -9.8 m/s2 which is gravity
Initial velocity on the Y axis is 0, on the X axis is 12 m/s
Inital position is 20 mts above the ground.
It takes the water 1.01 seconds to reach the other building.
THe distace from one building to the other is 12.11 meters.
Explanation:
In order to solve this you just need to carefully read the problem and the data you are given, and use the formula for height in free fall:
So first the data, we know that the water is coming out at a height of 20 meters since the building is 19 meters tall and the fireman is holding the firehose 1 meter above it, and the water is hitting the second building at a height of 15 meters, that means that the water is travelin -5meters.
Gravity as it doesn´t say otherwise would be 9.8m/s2 since that is gravity on earth, and water is leaving the firehose at 12m/s horizontally.
We can calculate the time by using the height formula fro free fall:
So it takes 1.009 seconds for the water to frop from 20 to 15 meters, as the horizontal velocity remains the same we just multiply it by the time and we get the horizontal distance between the two buildings and that would be:
12.11 meters.
Calculate the circumference of the circular path of the wheel by the equation,
C = 2πr
where C is the circumference,
r is the radius
Substituting the known values,
C = 2(π)(0.487 m) = 3.06 m
Then, period of the motion will be determined by dividing the number of rotations done,
T = (3.06 m) / (5.75 /s) = 0.53 s
<em>ANSWER: 0.53 s</em>
Answer:
runway use is 3307.8 feet
Explanation:
given data
velocity = 140 kts = 140 × 0.5144 m/s = 72.016 m/s
time = 28 seconds
weight = 28000 lbs
to find out
How many feet of runway was used
solution
we will use here first equation of motion for find acceleration
v = u + at ..............1
here v is velocity given and u is initial velocity that is 0 and a is acceleration and t is time
put here value in equation 1
72.016 = 0 + a(28)
a = 2.572 m/s²
and
now apply third equation of motion
s = ut + 0.5×a×t² .......................2
here s is distance and u is initial speed and t is time and a is acceleration
put here all value in equation 2
s = 0 + 0.5×2.572×28²
s = 1008.24 m = 3307.8 ft
so runway use is 3307.8 feet
