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3 years ago

Why might scientists conduct multiple trial experiments rather than rely on a single trial?

1 answer:

7 0

Scientists conduct multiple trial experiments because one test might not be as reliable as multiple trials. Another reason they conduct multiple trials is because the scientific method says to conduct multiple experimental tests.

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A novelty golf ball of mass m is launched with an initial velocity v0 = (25i + 13j) m/s and then follows a parabolic trajectory.

SVEN [57.7K]

Explanation:

(a)

The initial vertical velocity is 13 m/s. At the maximum height, the vertical velocity is 0 m/s.

v = at + v₀

0 = (-9.8) t + 13

t ≈ 1.33 s

(b)

Immediately prior to the explosion, the ball is at the maximum height. Here, the vertical velocity is 0 m/s, and the horizontal velocity is constant at 25 m/s.

v = √(vx² + vy²)

v = √(25² + 0²)

v = 25 m/s

(c)

Momentum is conserved before and after the explosion.

In the x direction:

m vx = ma vax + mb vbx

m (25) = (⅓ m) (0) + (⅔ m) (vbx)

25m = (⅔ m) (vbx)

25 = ⅔ vbx

vbx = 37.5 m/s

And in the y direction:

m vy = ma vay + mb vby

m (0) = (⅓ m) (0) + (⅔ m) (vby)

0 = (⅔ m) (vby)

vby = 0 m/s

Since the vertical velocity hasn't changed, and since Fragment B lands at the same height it was launched from, it will have a vertical velocity equal in magnitude and opposite in direction as its initial velocity.

vy = -13 m/s

And the horizontal velocity will stay constant.

vx = 37.5 m/s

The velocity vector is (37.5 i - 13 j) m/s. The magnitude is:

v = √(vx² + vy²)

v = √(37.5² + (-13)²)

v ≈ 39.7 m/s

7 0

4 years ago

I can’t figure this out!!! Answer what you can , please.

tigry1 [53]

a/b. The ball has velocity vector at time $t$

$\vec v=(v_x,v_y)=(v_0\cos63^\circ,v_0\sin63^\circ-gt)$

where $v_0=16\dfrac{\rm m}{\rm s}$ is the ball's initial speed and $g=9.8\dfrac{\rm m}{\mathrm s^2}$ .

c. At its highest point, the ball has 0 vertical speed. This occurs when

$v_0\sin63^\circ-gt=0\implies t=1.5\,\mathrm s$

d. Recall that

${v_y}^2-{v_{0y}}^2=-2g\Delta y$

so that at its highest point,

$0^2-(v_0\sin63^\circ)^2=-2g\Delta y\implies\Delta y=10\,\mathrm m$

e. This is just twice the time it takes for the ball to reach its maximum height, $t=2.9\,\mathrm s$ .

f. The ball's horizontal position after time $t$ is

$v_0\cos63^\circ\,t$

so that after the time found in part (f), the ball has traveled

$v_0\cos63^\circ(2.9\,\mathrm s)=11\,\mathrm m$

4 0

4 years ago

Newton’s second law of motion states that an object with a heavier mass will have more acceleration than an object with a smalle

wolverine [178]

This is true. I hope this helps! :)

5 0

3 years ago

Read 2 more answers

A satellite orbiting the earth is directly over a point on the equator at 12:00 midnight every four days. It is not over that po

Mrrafil [7]

Answer:

106417026.88435 m

Explanation:

T = Time period of the satellite = 4 days

m = Mass of the Earth = 5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

Time period is given by

$T=2\pi\sqrt{\dfrac{r^3}{GM}}\\\Rightarrow r=\left(\dfrac{T^2GM}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=\left(\dfrac{(4\times 24\times 60\times 60)^2\times 6.67\times 10^{-11}\times 5.972\times 10^{24}}{4\pi ^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=106417026.88435\ m$

The radius of the satellite's orbit is 106417026.88435 m

5 0

3 years ago

What is a concave lens?

ozzi

A concave lens is a lens that has at least one of its surfaces or both surfaces curved inwards. Due to this reason, this lens diverges the light that falls on it and hence is also called a diverging lens. The concave lens is thinner in the middle compared to its edges. These are used in flashlights, binoculars, telescopes, etc.
Please see attached image for reference.

5 0

3 years ago