Answer:
P(120< x < 210) = 0.8664
Step-by-step explanation:
given data
time length = 20 year
average mean time μ = 165 min
standard deviation σ = 30 min
randomly selected game between = 120 and 210 minute
solution
so here probability between 120 and 210 will be
P(120< x < 210) =
P(120< x < 210) = ![P(\frac{-45}{30}< \frac{x-\mu }{\sigma }](https://tex.z-dn.net/?f=P%28%5Cfrac%7B-45%7D%7B30%7D%3C%20%5Cfrac%7Bx-%5Cmu%20%7D%7B%5Csigma%20%7D%20%3C%5Cfrac%7B45%7D%7B30%7D%29)
P(120< x < 210) = P(-1.5< Z < 1.5)
P(120< x < 210) = P(Z< 1.5) - P(Z< -1.5)
now we will use here this function in excel function
=NORMSDIST(z)
=NORMSDIST(-1.5)
P(120< x < 210) = 0.9332 - 0.0668
P(120< x < 210) = 0.8664
Yes, it does! evaluating and solving an expression are the same thing!
Answer:
45, 36
Step-by-step explanation:
let x y minutes be the time for pipes to fill the tank, let n be the water needed to fill the tank.
x-y=9
(n/x)*20+(n/y)*20=n
n is removed by dividing the 2nd equation by n
here u get:
(1/x+1/y)*20=1
you sub x=9+y into the above equation
1/y+1/(9+y)=1/20
((9+y)+(y))*20=(9+y)(y)
180+40y=9y+y2
y2-31y-180=0
then use the quadratic formula and u will find y=36 or -5
-5 is rejected because it is negative
x=36+9=45
therefore it is 36 mins and 45 mins
Answer:
![d=20](https://tex.z-dn.net/?f=d%3D20)
Step-by-step explanation:
![d+67=87](https://tex.z-dn.net/?f=d%2B67%3D87)
Subtract 67 from both sides
![d=20](https://tex.z-dn.net/?f=d%3D20)
Hope this is helpful