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3 years ago

I NEED HELP!!!

Mathematics

2 answers:

zepelin [54]3 years ago

6 0

In order to answer this one, it's really really really really helpful if you know what the law of cosines says. In fact it's absolutely necessary. The law of cosines says if you know two sides of a triangle and the angle between them then you can use that information to find the length of the third side. In the picture you know the lengths of two sides and you know the angle between them. So you can use the law of cosines to find the length of the third sidethat. That's side AC.

saveliy_v [14]3 years ago

6 0

Answer:

A) AC

Explanation :-

AC is the measurement of acute triangle ABC can you find by direct substitution of the labeled measures in the Law of Cosines

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On a certain hot summer's day, 477 people used the public swimming pool. The daily prices are 1.50 for children and 2.25 for ad

Akimi4 [234]

Answer:

212 children, and 265 adults

Step-by-step explanation:

To find the number of children and adults, we can set up a systems of equations.

x= number of children

y= number of adults

Equation 1: Price

1.50x+2.25y=914.25

Equation 2: Total number of people

x+y=477

Now, let's solve the equation using substitution.

Rearrange the second equation to solve for one variable.

x+y=477

x=477-y

Now plug x equals into the first equation, and solve for y.

1.50x+2.25y=914.25

1.50(477-y)+2.25y=914.25

715.5-1.50y+2.25y=914.25

715.5+0.75y=914.25

0.75y=198.75

y=265

We just solved for the number of adults. Now let's plug y equals into the second equation to find the number of children.

x+y=477

x+265=477

x=212

7 0

2 years ago

WILL MARK YOU BRAINLIEST

qaws [65]

Answer:

6 and 7

Step-by-step explanation:

now make me brainliest

7 0

3 years ago

The function f(x) = −x^2 − 5x + 50 shows the relationship between the vertical distance of a diver from a pool's surface f(x), i

pychu [463]

Set the function to equal zero:

$-x^2 - 5x + 50 = 0$

To find the zeros, or solutions, to this problem, we will use the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Plug the values into the equation:

$a = -1, b = -5, c = 50$

$x=\frac{5\pm\sqrt{-5^2-4(-1)(50)}}{2(-1)}$

$x=\frac{5\pm\sqrt{25+200}}{-2}$

$x=\frac{5\pm15}{-2}$

Solve for both plus and minus:

$\frac{5 + 15}{-2} = \frac{20}{-2} = -10$

$\frac{5 - 15}{-2} = \frac{-10}{-2} = 5$

$x = -10, x = 5$

The question cannot use a negative value for x, as the diver cannot dive a negative distance from the board.

The answer is '<span>x = 5; the diver hits the water 5 feet away horizontally from the board', because x represents the horizontal distance away from the board.</span>

4 0

3 years ago

What is (t)? 0=18000*0.988^t

lutik1710 [3]

0=1. The answer is No Solution.

6 0

3 years ago

Suppose log subscript a x equals 2, space log subscript a y equals 5, and log subscript a z equals short dash 3. Find the value

sineoko [7]

The value of the logarithmic expression $\log _a (\frac{x^3y}{z^4} )$ is 24.

Given the following logarithmic expressions $\log _ax = 3, \log _ay = 7, \log _az = -2$ , we are to find the value of $\log _a (\frac{x^3y}{z^4} )$

from the above $\log _ax = 3, x = a^3$

$\log _ay = 7, y = a^7$

Substituting x = $a^3$ , y = $a^7$ and z = $a^{-2}$ into the log function $\log _a (\frac{x^3y}{z^4} )$ we will have;

$\log _a (\frac{x^3y}{z^4} )\\=\log _a (\frac{(a^3)^3 \times a^7}{(a^{-2})^4} )\\= \log _a (\frac{a^9 \times a^7}{a^-^8} )\\= \log _a (\frac{a^1^6}{a^-^8} )\\= \log _a (\frac{x^3y}{z^4} )\\= \log _a a^2^4\\= 24 \log _a a\\= 24 \times 1\\= 24$

Hence, the value of the logarithmic expression is 24

<h3>What is logarithmic expression?</h3>

In an exponential equation, the variable is expressed as an exponent. An equation using the logarithm of an expression containing a variable is referred to as a logarithmic equation.
Check to determine if you can write both sides of the equation as powers of the same number before you attempt to solve an exponential equation.

To learn more about logarithmic expression with the given link

brainly.com/question/24211708

#SPJ4

3 0

1 year ago