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3 years ago

Factor this trinomial. answer should have 2 binomials. y^2+5y-36

Mathematics

1 answer:

tino4ka555 [31]3 years ago

4 0

<span>Trinomial=y^2+5y-36
Factorise= y^2+9y-4y-36
= y(y+9)-4(y+9)
= (y-4)(y+9)</span>

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3 years ago

Rewrite 56+32 as the product of the GCF and a sum.

Vitek1552 [10]

56 = 2 x 2 x 2 x 732 = 2 x 2 x 2 x 2 x 2
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3 years ago

Sam wants to build a wooden deck on his patio, which is in the shape of a parallelogram. The area of the patio is 280 ft 2. Find

Radda [10]

Answer: The base is 18.3ft

Sam wants to build a wooden deck on his patio, which is in the shape of a parallelogram. The area of the patio is 280 ft2. Find the base. Round your answer to the nearest foot. (height=5x)(base=6x)

Step-by-step explanation:

Given;

Area = 280ft^2

height = 5x

Base = 6x

The area of the parallelogram A can be written as;

Area = base × height

A = b×h

Substituting the values of Area, base and height.

280 = 5x × 6x

280 = 30x^2

x^2 = 280/30

x = √(280/30)

Since the base = 6x ;

Substituting the value of x.

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3 years ago

A grain trader buys the following amounts from three suppliers: 3,200 pounds, 7,200 pounds and 600 pounds. What is the total wei

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Answer:

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Step-by-step explanation:

3200+7200+600=11000

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2 years ago

Read 2 more answers

SHOW YOUR WORK, <br><br>PLEASE HELP!!!!!!!!!

Shkiper50 [21]

To find the inverse, we swap the variables y and x, then solve for the new y.

3a. $y=\frac{3}{x-1}$

Swapping the variables: $x=\frac{3}{y-1}$
Solving for y: $x(y-1)=3 \\ y-1= \frac{3}{x} \\ y=1+\frac{3}{x}$
The domain of this inverse is $x ≠ 0$ .
3b. $y=x^2-1$

Swapping: $x = y^2 - 1$
Solving for y: $y^2 = x + 1 \\ y = \sqrt{x+1}$
The domain of this inverse is $x ≥ -1$ .
3c. $y=\sqrt[3]{\frac{x-7}{3}}$
Swapping: $x=\sqrt[3]{\frac{y-7}{3}}$
Solving for y: $x^3=\frac{y-7}{3} \\ y-7=3x^3 \\ y=3x^3+7$
The domain of this inverse is all real numbers.
4a. $y=\frac{3}{x-1}$ , $y=1+\frac{3}{x}$
$y=\frac{3}{(1+\frac{3}{x})-1} \\ y=\frac{3}{(\frac{3}{x})} \\ y=x$
$y=1+\frac{3}{(\frac{3}{x-1})} \\ y = 1+(x-1) \\ y = x$

4c. $y=\sqrt[3]{\frac{x-7}{3}}$ , $y=3x^3+7$
$y=\sqrt[3]{\frac{(3x^3+7)-7}{3}} \\ y=\sqrt[3]{\frac{3x^3}{3}} \\ y=\sqrt[3]{x^3} \\ y=x$
$y=3(\sqrt[3]{\frac{x-7}{3}})^3+7 \\ y = 3({\frac{x-7}{3}})+7 \\ y = (x-7)+7 \\ y=x$

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3 years ago