Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of
(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min
and flows out at a rate of
(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min
Then the net flow rate is governed by the differential equation
Solve for S(t):
The left side is the derivative of a product:
Integrate both sides:
There's no sugar in the water at the start, so (a) S(0) = 0, which gives
and so (b) the amount of sugar in the tank at time t is
As , the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.
Part. %
------ = -------
Whole 100
816. X
------- = ------
850. 100
850x=81600
-------- ---------
850. 850
X=96
96% of seats were sold
Answer:
Below in bold.
Step-by-step explanation:
In each case you divide top and bottom by the GCF.
A. The GCF of 45 and 56 is 1.
so the answer is 45/56.
B. 15/16 (GCF = 1)
C. Here the GCF is 5 so the answer is (35/5) / (80/5)
= 7/16.
D. 5/6 (GCF is 4).
<span>Let C denote the number of candidates they interview and E the number of employees they train.
</span>
<span>If it takes 20 hours and $400 to interview a candidate, then it takes 20C hours and $400C to interview C candidates.
</span>
If <span>it takes 120 hours and $3600 to train an employee, then it takes 120E hours and $3600E to train E employees.
</span>
Company has less than <span>$95000, then 400C+3600E<95000.
</span>
Company <span>wants to spend at most 470 hours, then
.
</span>
<span>You obtain the system of two inequalities:
</span>
Then you can solve this system according to your demands.
<u><em>The answer is 129 </em></u><em> i hope this helps </em>
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