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viva [34]
3 years ago
15

PLEASE HELP!

Mathematics
1 answer:
Oksana_A [137]3 years ago
5 0

Answer:

Plumber A

C. y=(150+40)x

Plumber B

B. y=40x+150

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Number 4 only plzzz help asap its due tomorrow
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B:
i=43 degrees
ii= 2 minutes
C:
10 degrees per minute
Sorry that's all I got
7 0
3 years ago
Find the solution set for the following equation. <img src="https://tex.z-dn.net/?f=-%5Csqrt%28x%29%3D5" id="TexFormula1" title=
andrey2020 [161]

Answer:

Solution set = {25}

Step-by-step explanation:

=> -\sqrt{x} =5

Dividing both sides by -1

=> \sqrt{x} = -5

Taking square on both sides

=> x = 25

<em><u>Solution set = {25}</u></em>

3 0
3 years ago
15 POINTS‼️‼️‼️<br><br> Part B: Solve for x. Show your work.
Musya8 [376]

Answer:

Step-by-step explanation:

A straight line adds up to 180 degrees, therefore 3x+6x = 180

9x = 180

x = 20

7 0
3 years ago
mary went to her local Zoo where 55% of it's exhibit feature reptiles if the zoo features 20 exhibits in total how many of the z
IceJOKER [234]
Hello!

To find this you have to find what 55% of 20 is

You can do this by doing 20 * 0.55

0.55 is 55% as a decimal

This gives us the answer of 11

Hope this helps!
8 0
3 years ago
Read 2 more answers
segment BC is an are of a circle with radius 30.0 cm, and point P is at the center of curvature of the arc Segment DA is an arc
Elan Coil [88]

Answer:

The magnetic field is B = 3.87 *10^{-6} \ T

Direction is inward

 

Step-by-step explanation:

The diagram for this question is shown on the first uploaded image  

From the question we are told that

      The radius of  BC is  r_{BC} =  30 \ cm  =  0.30 \ m

      The radius of  DA is r _{DA} =  20 \ cm =  0.20 \ m

      The length of CD is  r_{CD} =  10 cm =  0.1 \ m

      The length of AB is  r_{AB} =  10 cm =  0.1 \ m

      The current is  I  =  11.4A

The magnetic field is mathematically represented as

      B =  B_{BC} +  B_{DA} + B_{CD} + B_{AB}

       B =  \frac{\mu_o I}{4 \pi } [ \frac{\theta_{DA}}{r_{DA}} + \frac{\theta_{BC}}{r_{BC}}+ \frac{\theta_{CD}}{r_{CD}}+\frac{\theta_{AB}}{r_{AB}}]

        Where

                 \theta_{BC} = \theta_{DA} =  \frac{2\pi}{3}

Where  \frac{2 \pi}{3}  =  120^o

                \theta_{CD} = \theta_{AB}  =  0^o

so

        B =  \frac{\mu_o I}{4 \pi } [ \frac{\frac{2\pi}{3} }{0.20} - \frac{\frac{2\pi}{3}}{0.30}}+ \frac{0}{0.10}+\frac{0}{0.10}]

         B = 3.87 *10^{-6} \ T

The direction is into the page

    This because the magnitude of the magnetic field due to arc BC whose direction is outward is less than that of DA whose direction is inward

This is because according to Fleming's Left Hand Rule  the direction of current is perpendicular to the direction of magnetic field so since  current in arc BC and DA are moving in opposite direction their magnetic field will also be moving in opposite direction

3 0
3 years ago
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