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choli [55]
4 years ago
13

The Lincoln Middle School Band is planning a bus trip to a band competition. There are 136 members in the band, and each bus wil

l hold 32 people. How many buses are needed for the trip?
Mathematics
2 answers:
konstantin123 [22]4 years ago
6 0
5 buses.
32 + 32 + 32 +32 = 128. 4 buses will hold 32 people.

136-128 = 8. 1 bus will hold 8 peope
Alex787 [66]4 years ago
6 0

5 buses because 126 divided by 32 is 4.25, but you can leave people out of a bus so it’ll be 5 buses

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List 7 integers that meat all the requirements Two of the integers are 6 units apart but they are a little closer than two of th
Alex Ar [27]
I don't know. 19? Hope this could help! ;)

4 0
3 years ago
Heather can complete two problems in ten minutes, and when she started she had three problems done. joel can complete three prob
zzz [600]
 heather can do 2 problems in 10 minutes....60 minutes in an hr
2/10 = x / 60...2 problems to 10 min = x problems to 60 min
10x = 120
x = 120/10
x = 12....so she can do 12 problems in 1 hr

Joel can complete 3 problems in 15 minutes...
3/15 = x / 60
15x = 180
x = 180/15
x = 12....so he can do 12 problems in 1 hr

so 24 problems can be done in 1 hr

Heather started with 3 problems done and Joel started with 2 problems done....added = 5 problems already done

and it is asking between 30 and 50 hrs.....so there is no equal sign in ur problem

ur answer is : 30 < 24x + 5 < 50 <==




5 0
3 years ago
According to Scarborough Research, more than 85% of working adults commute by car. Of all U.S. cities, Washington, D.C., and New
tamaranim1 [39]

Answer:

The 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha /2}\frac{\sigma}{\sqrt{n}}

Here the population standard deviation (σ) is not provided. So the confidence interval would be computed using the <em>t</em>-distribution.

The (1 - <em>α</em>) % confidence interval for population mean (<em>μ</em>) using the <em>t</em>-distribution is:

CI=\bar x\pm t_{\alpha /2,(n-1)}\frac{s}{\sqrt{n}}

Given:

\bar x=27.97\\s=10.04\\n=25\\t_{\alpha /2, (n-1)}=t_{0.01/2, (25-1)}=t_{0.005, 24}=2.797

*Use the <em>t</em>-table for the critical value.

Compute the 99% confidence interval as follows:

CI=27.97\pm 2.797\times\frac{10.04}{\sqrt{25}}\\=27.97\pm5.616\\=(22.354, 33.586)\\\approx(22.35, 33.59)

Thus, the 99% confidence interval for the mean commute time of all commuters in Washington D.C. area is (22.35, 33.59).

8 0
3 years ago
Cosec^2θ-1/cosec^2θ=cos^2θ​
denis-greek [22]

cosec(2t)=1/sin(2t) ==> 1/(2×cos(t)×sin(t))

cos(2t)= 1-2sin²t

or 2cos²t-1

or cos²t - sin²t

after we knew this informations we have to write it in the question

1/2×sint×cost-1/1/2×sint×cost=cos2t

-2×sint×cost+1/2sint×cost/1/2sint×cost=cos2t

the 2sint×cost will gone

-2×sint×cost+1=cos2t

lets take cos2t =1-2sin²t

-2×sint×cost+1=1-2sin²t

-2sint×cost=-2sin²t

cost=sint

that means the t is equal to 45 because sin45 and cos45 equal to √2/2

hopefully i didn't waste your time by reading and not understanding my English is not that good sorry

6 0
3 years ago
Read 2 more answers
PLS ANSWER IT QUCK PLS PLS PLS PLS PLS
Liono4ka [1.6K]

Answer:

87 !

Step-by-step explanation:

5 0
3 years ago
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