Answer: 6/12 are white, 3/12 are colored and 3/12 are albino.
Step-by-step explanation: If the horses are white and their parents are ccww (albino) and CCWw (white horse), according to Mendel's premises, they both must be CcWw, since the crossing provides one C from one parent and other c from the other parent, one W and the other w. Using Mendel's chess and the principle of independent segregation, the crossing between CcWw results in the following fenotypical ratio:
1/16 CCWW (lethal)
2/16 CCWw (white)
2/16 CcWW (lethal)
4/16 CcWw (white)
1/16 CCww (normal)
2/16 Ccww (normal)
2/16 ccWw (albino)
1/16 ccWW (lethal)
1/16 ccww (albino)
Excluding the 4 individuals that have the lethal locus, we have 6/12 that are white (2/12 + 4/12) and 3/12 (1/12 + 2/12) that are colored. Also, there are 3/12 of albino individuals as well.
Answer:
83.72
Step-by-step explanation:
26 percent *322 =
(26:100)*322 =
(26*322):100 =
8372:100 = 83.72
<span>3a^2+12a = 3a(a+4)
...</span>
1 (square) is 2/9, .22 repeating, and 22 2/9%
2. (circle) is 1/3, .33 repeating, and 33 1/3%
3. (star or circle) is 7/9, .77 repeating, and 77 7/9% sorry I couldn't finish the rest of them. dad told me to get off the computer.