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emmasim [6.3K]
3 years ago
8

Which one of the following terms is used to describe the bending of waves and subsequent spreading around obstacles or the edges

of an opening?
A) refraction
B) diffraction
C) interference
D) coherence
E) sonoluminescence
Physics
1 answer:
natulia [17]3 years ago
7 0

Answer:

B) diffraction

Explanation:

  • It is the bending of the waves around the edge of an obstacle that is encountered by the wave in its path.
  • The size of the object from the initial direction of the wave to its edge must be of the same order as the wavelength of the wave.
  • Longer the wavelength greater is the diffraction.
  • For a particular wavelength the diffraction is maximum when the size of the gap is equal to the size of the object.
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Which of the following is evidence that supports the idea of uniformitarianism?
Inga [223]
D. rates of soil erosion are much lower during droughts that last several years
5 0
3 years ago
A gymnast is swinging on a high bar. The distance between his waist and the bar is 0.905 m, as the drawing shows. At the top of
Citrus2011 [14]

Answer:

5.959 m/s

Explanation:

m = Mass of gymnast

u = Initial velocity

v = Final velocity

h_i = Initial height

h_f = Final height

From conservation of Energy

\frac{1}{2}mv^2+mgh_f=\frac{1}{2}mu^2+mgh_i\\\Rightarrow\frac{1}{2}mv^2+mg0=\frac{1}{2}m0^2+mgh_i\\\Rightarrow \frac{1}{2}mv^2=mgh_i\\\Rightarrow v=\sqrt{2gh_i}

h_i=2r

v=\sqrt{4gr}\\\Rightarrow v=\sqrt{4\times 9.81\times 0.905}\\\Rightarrow v=5.959\ m/s

Velocity of gymnast at bottom of swing is 5.959 m/s

5 0
3 years ago
To the nearest square foot, how many square feet are there in an area of 4.4 square meters?
vichka [17]

Answer:

    4.4 square meters = 47 square foot

Explanation:

We have

    1 meter = 3.28084 foot

    1 square meter = 3.28084 x 3.28084 square foot = 10.76 square foot

    4.4 square meters = 4.4 x 10.76 = 47.36 square foot = 47 square foot

    4.4 square meters = 47 square foot

3 0
3 years ago
What is the speed of sound at 33 °C (m/s)? For a frequency of 5 kHz, how large do you expect the wavelength to be (m)?
Vedmedyk [2.9K]

Answer:

-The speed of sound at 33°C is 362.8 m/s.

-The wavelength at a frequency at 5 kHz is 0.07256 m .

Explanation:

let v = 343 m/s be the speed of sound.

let T be the temperature.

then the speed of sound V, at 33°C is given by:

V = v + 0.6×T

   = 343 + 0.6×33

   = 362.8 m/s

Therefore, the speed of sound at 33°C is 362.8 m/s.

the wavelength at a frequency of f = 5kHz = 5000 Hz is given by:

λ = V/f

  = (362.8)/(5000)

  = 0.07256 m

Therefore, the wavelength at a frequency at 5 kHz is 0.07256 m .

7 0
3 years ago
He instruction booklet for your pressure cooker indicates that its highest setting is 11.1 psi . you know that standard atmosphe
blagie [28]

Given that,

Atmospheric Pressure = 14.7 psi

Cooking Pressure = 14.7 +11.1 = 25.8 psi

Take, Atmospheric Temperature = 25 °C

Cooking Temperature = ??

Since, we know that Gas equation is given by:

PV = nRT

or

P ∝ T

P1 / T1 = P2 / T2

14.7/ 25 = 25.8/ T2

T2 = 25*25.8/14.7

T2 = 43.87 °C

The cooking pressure will be 43.87 °C.

5 0
3 years ago
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