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kiruha [24]
3 years ago
10

Steve does 80 J of work to a rope threaded through a pulley and attached to a crate of anvils. The tension of the rope is 10 N a

nd the crate rises 4 m while Steve pulls. What is the efficiency of the pulley? [Hint: how much work was done on the crate?]
a) (A) 0.07 or 7 %
b) (B) 0.2 or 20 %
c) (C) 0.5 or 50 %
d) (D) 1 or 100 %
Physics
2 answers:
Ivahew [28]3 years ago
6 0

Answer:

The Answer is (B)

Explanation:

zimovet [89]3 years ago
5 0
The answer would be letter b
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rjkz [21]
4.2*9.8\\41.16

41.16 meters
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What tripositive ion has the electron configuration [kr] 4d3 ? what neutral atom has the electron configuration [kr] 5s 2 4d2 ?
tigry1 [53]

(a)

Electronic configuration is given as follows:

[Kr]4d^{3}

Since, this is the electronic configuration of ion with+3 that means 3 electrons are removed. On adding the 3 electrons, the electronic configuration of neutral atom can be obtained.

Thus, electronic configuration of neutral atom is [Kr]4d^{5}5s^{1}.

The atomic number of Kr is 36, thus, total number of electrons become 36+6=42.

This corresponds to element: molybdenum. Thus, the tripositive atom will be Mo^{3+}.

(b) The given electronic configuration is [Kr]5s^{2}4d^{2}.

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This corresponds to element zirconium, represented by symbol Zr.

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3 years ago
How do i find the weight of the suitcase<br>pls help asap​
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2 years ago
How to calculate F2?<br> m=16.4kg<br> f1= 2.7n<br> angle=34.4
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Read 2 more answers
A. How far does a 100-newton force have to move to do 1,000 joules
Aloiza [94]

Work done by a force is given as the product of force and the distance moved by the force.

<h3>What is work done?</h3>

Work done is the product of force and the distance moved by the the force.

  • Work done = Force × distance

Thus, distance required by the 100 N force is given as:

  • Distance = work done/force

Distance = 1000/100 = 10 m

Distance to be moved is 10 m.

Force applied = work done/ distance

Force applied by the hoist = 500/2

Force applied by the hoist = 250 N

Distance moved in one push-up = 25 cm = 0.25 m

Work done by the athlete after one push-up = 250 × 0.25 m

Work done by the athlete = 62.5 J

Distance moved by the force = 0 m

Work done = 500 × 0 = 0 N

Therefore, for work to be done, force has to move a distance.

Learn more about work done at: brainly.com/question/25573309

5 0
2 years ago
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