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4 years ago

Solve by completing the square 6x-x^2-7

Mathematics

2 answers:

Slav-nsk [51]4 years ago

8 0

Answer:

6x-1/x^5

Step-by-step explanation:

Virty [35]4 years ago

5 0

Answer:

-(x-3)^2+2

Step-by-step explanation:

Use the formula (b/2)^2 in order to create a new term to complete the square.

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What ratio is equivalent to 21/27 with lower terms

goldfiish [28.3K]

7/9 because if you simplify 21/27 you have to divide it by something that can go into both equally, which in this case is 3

6 0

3 years ago

Read 2 more answers

Given the diagram below, find the value of MQR.

hoa [83]

Answer:

The answer is MQR= 48 degrees

Step-by-step explanation:

I got this answer from process of elimination. The first option was 48 degrees so I divided 48 by 3 and got 16 then I applied to (2x + 16): (2(16)+16) and got 48 which comfirmed my answer. Also I took the test and it was right so I know its correct.

5 0

3 years ago

(0.000010)(0.00055)(0.002)

jeka57 [31]

Answer:

$1.1*10^{-11}$

I used a calculator.

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3 years ago

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Taking a test i don’t know anything about please help

PilotLPTM [1.2K]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 4:</u>

The line of regression is $\hat y = a+bx$ where:

$a=\overline y-b \overline x$

$b=\frac{r*s_y}{s_x}$

We are given that $\overline y=75$ , $s_y=8$ , $\overline x=280$ , $s_x=30$ , and $r=0.60$ , therefore our slope, $b$ , is:

$b=\frac{r*s_y}{s_x}$

$b=\frac{(0.60)(8)}{30}$

$b=0.16$

Therefore, the slope of the regression line is 0.16, which can be used along with the values of $\overline y$ and $\overline x$ to find the constant $a$ :

$a=\overline y-b \overline x$

$a=75-(0.16)(280)$

$a=30.2$

This means our final regression line is $\hat y = 30.2 + 0.16x$

<u>Problem 5:</u>

The slope, $b=0.16$ , means that for every 1 point earned for a student's pre-exam total, their final exam score will increase by 0.16 points for each point they earned on the pre-exam.

<u>Problem 6:</u>

The y-intercept (or constant), $a=30.2$ , means that if a student's pre-exam total were 0, then they would expect to get a 30.2 on the final exam.

<u>Problem 7:</u>

$R^{2}=(0.60)^{2}=0.36=36\%$

<u>Problem 8:</u>

The fraction of variability (aka. coefficient of determination), $R^2$ , means that a certain proportion (or percentage) of the variance in the response variable can be explained by the explanatory variable. In context, this means that 36% of the variance in final exam scores can be explained by the pre-exam scores.

6 0

3 years ago

What is the classification of each system? Drag the answers into the boxes to match each system. {4x−2y=102x−y=5 {y=2x−3−2x y=−5

Rus_ich [418]

1. 4x − 2y = 10 and 2x − y = 5

Lines are coincident.

2. y = 2x − 3 and −2x + y = −5

Lines are parallel.

3. 2x − 5y = 14 and 3x + 4y = 10

Lines are intersecting.

<h2>Linear system</h2>

It is a system of an equation in which the highest power of the variable is always 1. A one-dimension figure that has no width. It is a combination of infinite points side by side.

<h3>Given</h3>

1. 4x − 2y = 10 and 2x − y = 5

2. y = 2x − 3 and −2x + y = −5

3. 2x − 5y = 14 and 3x + 4y = 10

<h3>Condition for the lines.</h3>

$\rm \dfrac{a_1}{a_2} \neq \dfrac{b_1}{b_2} \ \ \ \ \ \ \ \ \ \ \ Lines\ are\ intersecting\\\\\rm \dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} \neq \dfrac{c_1}{c_2}\ \ \ \ Lines \ are\ parallel\\\\\rm \dfrac{a_1}{a_2} = \dfrac{b_1}{b_2} = \dfrac{c_1}{c_2} \ \ \ \ Lines\ are\ coincident$

<h3>Drag the answers into the boxes to match each system.</h3>

1. 4x − 2y = 10 and 2x − y = 5

Lines are coincident.

2. y = 2x − 3 and −2x + y = −5

Lines are parallel.

3. 2x − 5y = 14 and 3x + 4y = 10

Lines are intersecting.

More about the linear system link is given below.

brainly.com/question/20379472

6 0

2 years ago