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expeople1 [14]
3 years ago
14

I need help with the Coordinate plane's

Mathematics
1 answer:
Anit [1.1K]3 years ago
4 0

Answer: ITS THE SECOND ONE

Step-by-step explanation:

BC THERE ARE X, AND Y SO BASSICLY YOU HAVE TO TAKE THE QUIRDENITS AND GET THERE BASE IN EVERY ON MAY I ASK YOU WHAT IS THIS ON IS IT ON IXL IF IT IS THEN I DID IT?

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mel-nik [20]

Answer:

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Step-by-step explanation:

8 0
3 years ago
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The first quartile of a data set is 72, and the third quartile is 92. Which of these values in the data set is an outlier ?
konstantin123 [22]

Answer: Option D

D. 41​

Step-by-step explanation:

A value x_i is considered an outlier if

x_i> Q_3 + 1.5IQR

or

x_i

Where

Q_3 is the third quartile

Q_1 is the first quartile

IQR is the interquartile range.

IQR = Q_3-Q_1

In this case:

Q_3=92\\Q_1=72

So

IQR = 92-72 =20

Q_3 + 1.5IQR = 92 + 1.5*20 = 122

Q_1 - 1.5IQR=72-1.5*20=42

Then the outlier values will be all those greater than 122 or less than 42

Therefore the answer is the option D.

8 0
3 years ago
Integer for a loss of $13
Reil [10]
-13 should be ur answer
4 0
3 years ago
What are the lateral area and the surface of the cone shown below?
Ierofanga [76]
\bf \textit{lateral surface area of a cone}\\\\
LA=\pi r\stackrel{slant~height}{\sqrt{r^2+h^2}}~~
\begin{cases}
r=radius\\
h=height\\
-------\\
r=11\\
\stackrel{slant~height}{\sqrt{r^2+h^2}}=24
\end{cases}\implies LA=\pi (11)(24)
\\\\\\
\boxed{LA=264\pi }\\\\
-------------------------------

\bf \textit{total surface area of a cone}\\\\
SA=\pi r\stackrel{slant~height}{\sqrt{r^2+h^2}}+\pi r^2~~
\begin{cases}
r=radius\\
h=height\\
-------\\
r=11\\
\stackrel{slant~height}{\sqrt{r^2+h^2}}=24
\end{cases}
\\\\\\
SA=\pi (11)(24)+\pi (11)^2\implies SA=264\pi +121\pi 
\\\\\\
\boxed{SA=385\pi }
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3 years ago
Answer these five journal problems with the same 3 questions for each problem.
vichka [17]

Answer:

Step-by-step explanation:

8 0
3 years ago
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