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vladimir2022 [97]
3 years ago
8

Help *****Graph Function*****

Mathematics
1 answer:
Alecsey [184]3 years ago
7 0

I believe the answer is B.



Sorry is it's not but i strongly believe it is!!!

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Consider the sequence 256,128,64,32 find the 12th term of the sequence
Akimi4 [234]

Answer:

It would be 0.125

Step-by-step explanation:

I hope this helps you.

8 0
3 years ago
Help plz im sorry if im asking to many questions
Zinaida [17]

Answer:

The 3rd one 50 - 12p = 26

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3√5 , KE = 8, LM:KN = 3:5 Find: KM, LM, KN, Area of KLMN
lora16 [44]
Q1)Find KM
As ME is perpendicular to KN, ∠KEM is a right angle
Therefore ΔKEM is a right angled triangle 
KE is given and and ME is also given, we need to find KM
for this we can use Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides.
KM² = KE² + ME²
KM² = 8² + (3√5)²
       = 64 + 9x5
KM = √109
KM = 10.44

Q2)Find LM
It is said that ratio of LM:KN is 3:5
Therefore if we take the length of one unit as x
length of LM is 3x
and the length of KN is 5x
KN is greater than LM by 2 units 
If we take the figure ∠K and ∠N are equal. 
Since the angles on opposite sides of the bases are equal then this is called an isosceles trapezoid. So if we draw a line from L that cuts KN perpendicularly at D, ΔKEM and ΔLDN are congruent therefore KE = DN
since KN is greater than LM due to KE and DN , the extra 2 units of KN correspond to 16 units 
KN = LM + 2x 
2x = KE + DN
2x = 8+8
x = 8
LM = 3x = 3*8 = 24

Q3)Find KN 
Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have;
same height ME = LD perpendicular distance between the 2 parallel sides 
same right angle when the perpendicular lines cut KN
∠K = ∠N 
when 2 angles and one side of one triangle is equal to two angles and one side on another triangle then the 2 triangles are congruent according to AAS theorem (AAS). Therefore KE = DN 
the distance ED = LM
Therefore KN = KE + ED + DN
 since ED = LM = 24
and KE + DN = 16
KN = 16 + 24 = 40
another way is since KN = 5x and x = 8
KN = 5 * 8 = 40

Q4)Find area KLMN
Area of trapezium can be calculated using the following general equation 
Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)
where perpendicular height - ME
2 parallel sides are KN and LM
substituting values into the general equation
Area = 1/2 * ME * (KN+ LM) 
         = 1/2 * 3√5 * (40 + 24)
         = 1/2 * 3√5 * 64
         = 3 x 2.23 * 32
         = 214.66 units²


8 0
2 years ago
Read 2 more answers
4 is added to the data set 22, 25, 31, 33, 24. Answer true or false for the following statements.
Vedmedyk [2.9K]

Answer:

The range and mean will increase - False

(because only range will increase, mean will decrease)

The mean and median will decrease - True

The mean will decrease but the median will stay the same - False

(Both of mean and median will decrease)

An outlier is more likely to change the median than the mean - False

(An outlier is more likely to change the mean than the median)

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3 years ago
Find the slope and the y-intercept of the graph of y+1=4/3x.
riadik2000 [5.3K]

Answer:

Slope = 4/3x; y-intercept = -1

Step-by-step explanation:

y + 1 = 4/3x

You have to write this equation in slope-intercept form (solve for y) if you want to find the slope and y-intercept

y + 1 = 4/3x

Subtract one from both sides

y + 1 - 1 = 4/3x - 1

y = 4/3x - 1

Now that we have the equation, you can now find the slope and y-intercept

y = mx + b; m is the slope and b is the y-intercept

So for y = 4/3x - 1, the slope is 4/3x and the y-intercept is -1

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3 years ago
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