To determine whether the crown was made of pure gold or not, we need to compare the density of gold (19.3 g/mL) to the density of the crown.
The formula for density is
we know the mass of the crown is 714 grams and its volume is 38.3 mL. (Because it displaces 38.3 mL of water)
Using this information, we can plug the numbers into our density formula to solve for the density of the crown.
The density of the crown is 18.6 g/mL, thus the crown was not made of pure gold, as that has a density of 19.3 g/mL. In conclusion, the goldsmith tried to screw over the king.
The mass of the solute required is 250.25 g.
<h3>What is the mass of the solute?</h3>
We know that the number of moles of the solute can be used to obtain the mass of the solute that is required. We can now try to find the mass of the solute that is required.
Concentration of the solution = 0.350M
Volume of the solution = 6.5 L
Number of moles of the solute = 0.350M * 6.5 L
= 2.275 moles
We now have the mass of the solute as;
2.275 moles * 110 g/mol
= 250.25 g
Th measured mass of the solute that we would have to use is 250.25 g.
Learn more about solute:brainly.com/question/7932885
#SPJ1
Missing parts;
A chemist wants to make 6.5 L of a .350M CaCl2 solution. What mass of CaCl2(in g) should the chemist use?
A-Aluminium sulphate.
B-Calcium Chloride.
C-Potassium sulphate.
D-Potassium Nitrate .
E-Calcium Carbonate.
<em>Answer:</em>
- The atom have a full valence electron shell.
<em>Explanation:</em>
- My question is that why covalent bonds take place?
Every atoms tends to from bond with another atoms in order to get nearest electronic configuration of nobel gases. They become stable when their valence shell become complete. So when covelant bond forms between atoms, share electrons to each other and stabilize themselves.
Answer:
The aromatic ringsare the number 1 and 2.
Identify which lone pairs are participating in resonance (in aromatic rings).
- One lone pair on the sulfur atom.
Explanation:
For a compound to be aromatic it has to comply with Hückel's Rule, which says that the quantity of electrons in the pi orbitals, has to be a multiple of
4n + 2
for n = 0, 1, 2, 3.
