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MArishka [77]
3 years ago
13

An unknown quantity of sugar was completely dissolved in water at 75 degrees Celsius to form a clear and colorless solution. The

temperature of the solution was then lowered to 25 degrees Celsius while being mixed.
Question 1: Was the solution at 75 degrees Celsius saturated, unsaturated or supersaturated?

Question 2: Explain your reason for choosing the answer in question 1.
Chemistry
1 answer:
Nataly_w [17]3 years ago
5 0

Answer:

67

Explanation:

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Explanation:cool thre answer is 009000000000.1 because you have to add them so ye

6 0
3 years ago
There are four different starting molecules that one might use to synthesize the illustrated alkyl halide as the major product u
Mkey [24]

Answer:

Explanation:

An electrophilic addition reaction occurs when an electrophile attacks a substrate, with the end result being the inclusion of one or many comparatively straightforward molecules along with multiple bonds.

In the given question, the hydrogen bromide provides the electrophile while the bromide is the nucleophile. The mechanism proceeds with the attack of the electrophile on the carbon, followed by deprotonation. This process is continued with a formation of carbocation and the bromide(nucleophile) finally bonds to the carbocation to form a stable product.

The first diagram showcases the possible various starting molecules for the synthesis while the second diagram illustrates their mechanism.

6 0
2 years ago
Which of the following provides cell support in an animal cell? A. microtubule B. mitochondria C. lysosomes D. vacuole
Viktor [21]

Answer:

D.

Vacuole

Explanation:

Hope this helps:)

4 0
3 years ago
Which of the following chemical formulas shows a covalent bond (a) CO2 (b) MgO (c) NaCL (d) HBr
AlexFokin [52]
The correct answer is A. CO2
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3 0
3 years ago
The rate constant k for a certain reaction is measured at two different temperatures:
bogdanovich [222]

Answer:

Ea=5.5 Kcal/mole

Explanation:

Let rate constant are K_1  and K_2  at temperature T_1  and T_2

By using Arrhenius equation at two different two different temperature,

Log K_1/K_2 =E_a/2.303R*(1/T_2 -1/T_2 );T_1=273+376=649K  ;K_1=4.8*10^8;T_2=273+280=553K  ;K_2=2.3*10^8;R=2 cal/(mole.K);Log (4.8*10^8)/(2.3*10^8 )=E_a/2.303R*(1/553K-1/649); Log 4.8/2.3=E_a/2.303R*96/358897 ;0.32=E_a/2.303R*96/358897;E_a=(0.32*2.303R*358897)/96;  

By putting value of R=2 cal/mole.K

E_a=5510.265cal/mole;

By rounding off upto 2 significant figure;

E_a=5.5Kcal/mole;

8 0
3 years ago
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