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Vesnalui [34]
3 years ago
6

1. General admission to the Fair is $10.00. Each ride costs $4.75. If Lisa has $75.00 to spend att Fair , what method cal be use

d to find out how many rides she can go on?​

Mathematics
2 answers:
TEA [102]3 years ago
8 0
The answer is option D because you have to subtract the amount the admission to the fair costs from the amount you started out with, so 75-10 which is 65. Then divide your money left over by the amount a ride costs to determine how many rides you can go on. 65/4.74 = 13.68, which means she can go on 13 rides. May I please get brainliest because I showed work :)
77julia77 [94]3 years ago
6 0

Answer:D

Step-by-step explanation:mark me brainliest

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a wheel has a diameter of 15cm. The wheel travels 50 metres. How many revolutions does the wheel complete?
TEA [102]

Answer:

106

Step-by-step explanation:

The diameter of the wheel is 15 cm or 0.15 m.

The circumference of the wheel is 0.15π m ≈ 0.47 m.

So the wheel moves 0.47 m with each revolution.

The wheel travels 50 m, so the number of revolutions is:

(50 m) / (0.47 m/rev) ≈ 106 revolutions.

8 0
3 years ago
What's the answer to this math problem
GarryVolchara [31]
Total number of marbles:
75 + 50 + 100 + 25 = 250

Probability of selecting a red marble:
25/250 (since 25 out of 250 marbles are red)
Since the top and bottom of this fraction are both divisible by 25, we can go ahead and divide them both by 25, simplifying to 1/10.

Probability of selecting a green marble:
50/250
Simplifies to 2/10
Simplifies to 1/5.

Probability of selecting a blue or orange marble
(75+100)/250
175/250
Simplifies to 7/10.

To find the probability that each event occurs in order, simply multiply them all together.

\frac{1}{10}\times\frac{1}{5}\times\frac{7}{10}=\frac{1\times1\times7}{10\times5\times10}=\boxed{\frac{7}{500}}
4 0
3 years ago
Read 2 more answers
Write 800 as the product of its prime factors.
Alex_Xolod [135]
800|2
800|2
400|2
200|2
100|2
50|2
25|5
5|5
1

800=2^5\cdot5^2


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Answer:

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Step-by-step explanation:

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