Answer:
<u><em>x>2</em></u>
Step-by-step explanation:
<u><em>x3+3x2=7x+6</em></u>
<u><em>x3+3x2−(7x+6)=7x+6−(7x+6)</em></u>
<u><em>x3+3x2−7x−6=0</em></u>
<u><em>(x−2)(x2+5x+3)=0</em></u>
<u><em>x−2=0 or x2+5x+3=0</em></u>
<u><em>x=2 or x=−0.6972243622680054 or x=−4.302775637731995</em></u>
<u><em>x<−4.302776</em></u>
<u><em>−4.302776<x<−0.697224</em></u>
<u><em>−0.697224<x<2</em></u>
<u><em>x>2(Works in original inequality)</em></u>
900,000 would be the nearest hundred thousand
sorry if it's wrong, but I did try
Answer: the correct answer is 20
Step-by-step explanation:
The formula for determining the distance between two points on a straight line is expressed as
Distance = √(x2 - x1)² + (y2 - y1)²
Where
x2 represents final value of x on the horizontal axis
x1 represents initial value of x on the horizontal axis.
y2 represents final value of y on the vertical axis.
y1 represents initial value of y on the vertical axis.
From the graph given,
x2 = - 7
x1 = 5
y2 = - 7
y1 = 9
Therefore,
Distance = √(- 7 - 5)² + (- 7 - 9)²
Distance = √(- 12²) + (- 16)²
= √(144 + 256) = √400
Distance = 20
Answer: Choice A) 90
The upper quartile, aka the third quartile (Q3), is visually represented by the right-side edge of the box, which is at 90 on the number line.
