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3 years ago

Whats the answer lol

Mathematics

2 answers:

kotegsom [21]3 years ago

7 0

I guess this is a free 5 points!

sweet-ann [11.9K]3 years ago

6 0

Whats the question lol

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Draw 8 lines that are between 1 inch and 3 inches long. Measure each line to the nearest fourth inch, and make a line plot

hammer [34]

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3 0

3 years ago

Read 2 more answers

To find 19 + (11+37), Lennie added 19 and 11. Then he added 37 to the sum. What property did he use ?

Ad libitum [116K]

19 + (11+37) = (19 + 11) + 37

Associative property of addition

3 0

3 years ago

Read 2 more answers

15 points for someone who can answer & explain this to me thanks

iris [78.8K]

Answer:

see explanation

Step-by-step explanation:

Given

$\frac{9}{a^2+9a+20}$ , $\frac{7a}{a^2+11a+28}$

Factor the denominators of both fractions

$\frac{9}{(a+4)(a+5)}$ , $\frac{7a}{(a+4)(a+7)}$

The lowest common denominator of both fractions is (a + 4)(a + 5)(a + 7)

Multiply numerator/denominator of first fraction by (a + 7)

Multiply numerator/denominator of second fraction by (a + 5 )

$\frac{9(a+7)}{(a+4)(a+5)(a+7)}$ , $\frac{7a(a+5)}{(a+4)(a+5)(a+7)}$ , then

$\frac{9a+63}{(a+4)(a+5)(a+7)}$ , $\frac{7a^2+35a}{(a+4)(a+5)(a+7)}$

8 0

2 years ago

A rectangular piece of metal is 25 in longer than it is wide. Squares with sides 5 in long are cut from the four corners and the

Licemer1 [7]

Answer:

The original length was 41 inches and the original width was 16 inches

Step-by-step explanation:

Let

x ----> the original length of the piece of metal

y ----> the original width of the piece of metal

we know that

When squares with sides 5 in long are cut from the four corners and the flaps are folded upward to form an open box

The dimensions of the box are

$L=(x-10)\ in\\W=(y-10)\ in\\H=5\ in$

The volume of the box is equal to

$V=(x-10)(y-10)5$

$V=930\ in^3$

$930=(x-10)(y-10)5$

simplify

$186=(x-10)(y-10)$ -----> equation A

Remember that

The piece of metal is 25 in longer than it is wide

$x=y+25$ ----> equation B

substitute equation B in equation A

$186=(y+25-10)(y-10)$

solve for y

$186=(y+15)(y-10)\\186=y^2-10y+15y-150\\y^2+5y-336=0$

Solve the quadratic equation by graphing

using a graphing tool

The solution is y=16

see the attached figure

Find the value of x

$x=16+25=41$

therefore

The original length was 41 inches and the original width was 16 inches

3 0

3 years ago

HELPPPPPP

SOVA2 [1]

Answer:

10^-99

10^-17

10^-5

10⁵

10¹⁴

10³⁰

8 0

2 years ago