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Anna71 [15]
3 years ago
13

When the exponent blank is applied to a nonzero base, the result is always 1

Mathematics
2 answers:
Anestetic [448]3 years ago
7 0

0

20char20char20char20char

yanalaym [24]3 years ago
3 0

When the exponent <em>zero</em> is applied to a nonzero base, the result is always 1 .

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ttttttttttttttttttttttthhhhhhhhhhhhhhhhhhhhhheeeeeeeeeeeeeeeeeeeeerrrrrrrrrrrrrrrrrrrreeeeeeeeeeeeeeeeeeeeee
Bumek [7]

Answer:

Step-by-step explanation:

(C)

5 0
3 years ago
The radio station gave away a discount coupon for every twelfth and thirteenth caller. Every twentieth caller received free conc
Snezhnost [94]

Answer:

60th caller.

the 12th caller would hit a number divisible by 20 at 60.

12,24,35,48,60

7 0
3 years ago
Read each problem carefully and solve as required then answer the questions that follow
zepelin [54]

Answer:

Step-by-step explanation:

1) Number of children = c

Number of adults = a

Total ticket = 250

c + a = 250 -------------------(I)

Cost of 'c' children tickets = 200c

Cost of 'a' adult tickets =  450a

Total cost = 76000

200c + 450a = 76000  ------------------(II)

Multiply (I) by (-200) and then add

(I)*(-200)          -200c - 200a = -50000

(II)                    <u> 200c + 450a = 76000 </u>

<u> </u>                                    250a = 26000

                                           a = 26000/250

a = 104

Plug in a = 104 in equation (1)

c + 104 = 250

         c = 250 - 104

        c = 146

2)Number of children = 146

Number of adults = 104

7 0
3 years ago
Verify this cofunction identity by using the difference identity for cosine. Show your work! cos⁡(π/2-θ)=sinθ
taurus [48]
Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ

π/2 = 90°
cos(π/2) = cos90° = 0.        sin(π/2) = sin90° = 1

cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ
</span>
                   = 0*cosθ + 1*sin<span>θ  = </span>sin<span>θ

Therefore  </span>cos(π/2 - θ) = sin<span>θ
 
QED   </span>
8 0
3 years ago
A ball is kicked into the air and follows the path described by h(t)= – 4.9t^2 + 6t + 0.6, where t is the time in seconds and h
miv72 [106K]
The maximum value can be determined by taking the derivative of the function.

(dh/dt) [h(t)] = h'(x) = -9.8t + 6

Set h'(x) = 0 to find the critical point

-9.8t + 6 = 0
-9.8t = -6
t = 6/9.8

Plug the time back into the function to find the height.

h(6/9.8) = -4.9(6/9.8)^2 + 6(6/9.8) + .6
= 2.4

And I don't understand your second question.
5 0
3 years ago
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