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olganol [36]
3 years ago
10

How to solve (x+2)^3/4=27

Mathematics
1 answer:
Gelneren [198K]3 years ago
5 0
Cross multiply so 27*4 = (x+2)^3
Then cube root 108 = x+2
(cube root 108)-2= x
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The two non-parallel sides of an isosceles trapezoid are each 7 feet long. The longer of the two bases measures 22 feet long. Th
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The length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

<h3>How to determine the length</h3>

The cosine rule is given as;

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c = \sqrt{7^2 + 22^2 - 2 * 7 * 22 cos 40}

c = \sqrt{533 - 308 * 0. 7660}

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Using sine rule

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Cross multiply

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a × 0. 8660 = 17. 24 × 0. 9397

a = \frac{16. 20}{0. 8660}

a = 18. 7 feet long

Thus, the length of the diagonal and the shorter base are 17. 24 feet and 18. 7 feet long respectively.

Learn more about  isosceles trapezoid here:

brainly.com/question/10187910

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