First, you need to change it from standard form to slope-intercept form. To do this, you have to add 3x to both sides. Now that y is by itself, divide by 5 on both sides. Your equation should now be y=3x+3. Then, graph the points. Your x-intercept should be at (-5,0) and your y- intercept should be at (0,3).
Suppose we wish to determine whether or not two given polynomials with complex coefficients have a common root. Given two first-degree polynomials a0 + a1x and b0 + b1x, we seek a single value of x such that
Solving each of these equations for x we get x = -a0/a1 and x = -b0/b1 respectively, so in order for both equations to be satisfied simultaneously we must have a0/a1 = b0/b1, which can also be written as a0b1 - a1b0 = 0. Formally we can regard this system as two linear equations in the two quantities x0 and x1, and write them in matrix form as
Hence a non-trivial solution requires the vanishing of the determinant of the coefficient matrix, which again gives a0b1 - a1b0 = 0.
Now consider two polynomials of degree 2. In this case we seek a single value of x such that
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This is the symmetric property of equality, and in a more general form it can be written as: if a=b then b=a.
This is not to be confused with communicative property, which says that the order doesn't matter in some operations, such as addition, and can be written as a+b=b+a
Answer:
The answer is 1.1
Step-by-step explanation:
0.4
+0.7
____
1 . 1
The frequency of A's would be 16.
The following would be the relative frequencies after the initial .08.
.18, .45, .15, .14.
To find the frequency of A, start by subtracting all of the other values from the total number. There are 200 total students, so subtract the other grade ranges.
200 - 36 - 90 - 30 - 28 = 16.
Now to find all of the frequencies, just divide each value by the total (200).
36/200 - .18
90/200 = .45
30/200 = .15
28/200 = .14
