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3 years ago

Describe, using words, how to solve the equation 6-4x=18. List any properties utilized in the solution.

1 answer:

3 0

First of all you need to make sure that each side has only letters and numbers, for this equation you first need to subtract 6 of each side, this way you can change the equation appearence without changing it's value, because if you do something in both sides of an equation, it's ok. After subtracting 6 of each side you can divide both sides for -4, this way you'll take only x in the left side and 12/-4 on the other, this way you will see that x = -3

6 - 4x = 18

6 - 4x - 6 = 18 - 6

-4x = 12

-4x/-4 = 12/-4

x = -3

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lana66690 [7]

Answer:

-4.65

Step-by-step explanation:

5.8-3.5=2.3

2.3 divided by 2=1.15

3.5+1.15=4.65

Answer: -4.65

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3 years ago

Item 5 Solve for b. − 1 3 b=9 What is the answer?

snow_lady [41]

Answer:

b = -27

Step-by-step explanation:

-1/3 b = 9

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3 years ago

Read 2 more answers

Factor the following expression using Reverse Distribution:<br> 6n-24

harkovskaia [24]

Answer:C 2(3n + 12)

Step-by-step explanation:

2 x 3n = 6n

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3 years ago

The mathematics department of a college has 6 male professors, 9 female professors, 5 male teaching assistants, and 6 female tea

Hitman42 [59]

Given:

6 male professores

9 female professores

5 male teaching assistants

6 female teaching assistants

Sol:.

$N(A\text{ or B)=N(A)+N(B)-N(A and B)}$

N (professors)

$\begin{gathered} =6+9 \\ =15 \end{gathered}$

N(Male)

$\begin{gathered} =6+5 \\ =11 \end{gathered}$

N(professors and male)

$=6$

N(professors OR male) = N(professors) + N(males) -N(professor OR male)

$\begin{gathered} N(\text{ Professors OR male)=15+11-6} \\ =20 \end{gathered}$

N(People to choose from)

$\begin{gathered} =6+9+5+6 \\ =26 \end{gathered}$

Then probablitiy is:

$\begin{gathered} =\frac{20}{26} \\ =\frac{10}{13} \end{gathered}$

Then the probability is 10/13

6 0

1 year ago

Investigate the difference between compounding annually and simple interest

Gennadij [26K]

Step-by-step explanation:

Simple interest formula

$A = P (1 + rt)$

Compound interest formula

$A = P(1 + \frac{r}{n})^{nt}$

$A = 5000 (1 + 0.025*1)\\A=5000(1.025)\\A=5125$

Simple interest is $125

. $A = 5000 (1 + \frac{0.025}{1})^{1*1} \\A=5000(1.025)\\A= 5125$

Compound interest is $125

c. the result for both a and b are the same

$A = 5000 (1 + 0.025*3) \\A=5000(1.075) \\A=5375$

the simple interest is $375

. $A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385$

the compound interest is $385

f. the result compared, compound interest is $10 more than simple interest

$A = 5000 (1 + 0.02*6) \\A=5000(1.12) \\A=5600$

the simple interest is $600

$A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869$

the compound interest is $4869

i. the result from g and h, h is over 8 times bigger than g.

j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h

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3 years ago