Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Answer:
both could be correct
Explanation:
It usually depends on how fast or how severe the change is, if its mild or happenes slowly over time they may adapt, if it is extreame or happenes very quickly the species could very well die out.
Answer:
Lysosomes are abundantly found in neuronal cells
Explanation:
Lysosomes are commonly found in the cells of nervous system and specifically abundant in neurons where it can observed at various stages of development. Lysosomes chief function is to degrade cellular wastes.The lysosomes extends from golgi saccules a vesicular body.Its main function is to bind with a membrane of vacuoles containing waste into which lysosomes releases it hydrolytic enzymes degraded waste inside the vacuoles itself and becomes secondary lysosomes.
pelvic blades rotated inward
<em>The </em><em>energy </em><em>released</em><em> by</em><em> the</em><em> </em><em>hydrolysis</em><em> </em><em>of </em><em>ATP </em><em>is </em> <em><u>7.3 kcal/mol of </u></em><em><u>energy.</u></em>
