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AVprozaik [17]
3 years ago
8

Help.........please.im done

Mathematics
1 answer:
olasank [31]3 years ago
7 0
2. 105-45=\2=60
4. 3rd Choice
5. 21 x5= 6(y+6)
105= 6y+36
Subtract 36
69= 6Y
Divide by 6
Y= 11.5
Answer IK= 17.5

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709,189<br> +348,987<br> ________
Leni [432]

Answer: 1058176

check:

1058176 - 709,189= 348,987

6 0
3 years ago
Given three consecutive integers with a sum of four times the second number, write an algebraic equation for this situation
Black_prince [1.1K]
<u>Define x:</u>

Let the first number be x.

1st number = x
2nd number = x + 1
3rd number = x + 2

<u>Construct equation:</u>
x + x + 1 + x + 2 = 4(x + 1)
3x + 3 = 4(x + 1)

Answer: 3x + 3 = 4(x + 1)
5 0
3 years ago
max bought 2 3/4 punds of green apples, 1 5/8 pounds of yellow apples, and 1 5/8 pounds red apples. the total cost was $5.40. wh
dangina [55]
2 3/4 + 1 5/8 + 1 5/8 =
2 + 1 + 1 = 4 (add the whole numbers)
3/4 + 5/8 + 5/8 = 6/8 + 5/8 + 5/8 = 16/8 = 2 (add the fractions)
4 + 2 = 6 total lbs

5.40 for 6 lbs = 5.40/6 = 0.90  (so the apples cost 90 cents per lb)
7 0
3 years ago
Solve for a. 2z=4a/m +3
Finger [1]

Answer:

<h3>                a = (2mz - 3m)/4</h3>

Step-by-step explanation:

2z = 4a/m +3

 -3        -3

2z - 3 = 4a/m

 ×m        ×m

(2z -3)m = 4a

     ÷4      ÷4

[(2z -3)m]/4 = a

a = (2mz - 3m)/4

4 0
3 years ago
£940 is divided between gavin, jim &amp; Krutika so that gavin gets twice as much as jim, and jim gets three times as much as kr
Zielflug [23.3K]

Answer:

$282

Step-by-step explanation:

We can think of it as an equation system. Lets find out the equations.

There are 3 people: Krutika, Gavin and Jim. Lets call k Kutrika's money and g and j Gavin's and Jim's money respectively.

So, as Gavin gains twice as Jim we can say that:

g = 2j

Then, as Jim gets 3 times more than Kutrika:

j = 3k

And, as the whole sum is 940:

k + j + g = 940.

Notice that both Kutrika's and Gavin's money have a relation to Jim's money, so we can try to write them as function of Jim's money.

If we part from j = 3k and divide both sides by 3:

j/3 = k

So, using this last equation and g = 2j, replacing in the equation that sums the money of everyone:

k + j + g = 940

j/3 + j + 2j = 940

Putting together all the terms that have j imply using 3 as common denominator:

j/3 + 3j/3 + 6j/3 = 940

10j/3 = 940

Dividing both sides by 10/3 (or multiplying by 3/10):

j = 940/ (10/3) = 282

So, Jim has $282. Now we can use the relations we defined to find k and g:

k = j/3 =$94

g = 2j = $564

4 0
3 years ago
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