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Ymorist [56]
3 years ago
7

A weightlifter presses a 400 n weight 0.5 m over his head in 2 seconds, what is the power of the weight lifter

Physics
1 answer:
Scrat [10]3 years ago
3 0
There are two ways to solve this problem. First we write the given.

Given: Force F = 400 N;  Height h = 0.5 m;  Time t = 2 s

Formula: P = W/t;  but Work W = Force x distance or W = f x d
 
Weight is also a Force, therefore:  W = mg, solve for Mass m = ?

m = w/g  m = 400 N/9.8 m/s²  m = 40.82 Kg

P = W/t = F x d/t  = mgh/t  P = (40.82 Kg)(9.8 m/s²)/2 s  

P = 100 J/s or 100 Watts

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Answer:

The value is  |v| = 7.39 \  m/s

Explanation:

From the question we are told that

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    The distance between the minimum and maximum external position is  d = 6.95 \ cm  = 0.0695 \ m

Generally the amplitude of the crank shaft is mathematically represented as

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3 years ago
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A. The force that causes the water on the lettuce to come off the lettuce and go to the walls of the bowl is centrifugal force.

<h3>What is centrifugal force?</h3>

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<h3>What is centripetal force?</h3>

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While centripetal force is directed towards to the center, the centrifugal force is directed away.

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Answer:

350 ft/s²

Explanation:

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Rounded to two significant figures, the magnitude of the acceleration is 350 ft/s².

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