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Gala2k [10]
3 years ago
13

Solve for x 4 ( x + 3 ) < 3 ( x + 5 )

Mathematics
2 answers:
forsale [732]3 years ago
7 0

Answer:

4x^2+9x-15<0

Step-by-step explanation:

x.4(x+3)<3(x+5)

(4x)(x+3)<3x+3x5

(4x)(x+3)<3x+15

4xx+4x.3<3x+15

4x^1+1+4x3x<3x+15

4x^2+12x<3x+15

(4x^2+12x)+(-3x-15)<(3x+15)+(-3x-15x)

4x^2+9x-15<3x-3x+15-15

4x^2+9x-15<0

Marianna [84]3 years ago
5 0

Answer:   x < 3

<u>Step-by-step explanation:</u>

4(x + 3) < 3(x + 5)

4x + 12 < 3x + 15          <em> Distributed</em>

 x + 12 < 15                   <em>Subtracted 3x from both sides</em>

       x  < 3                     <em>Subtracted 12 from both sides</em>

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Graph the function y = -2x + 1 using inputs of -1,0, 1, and 2.
Vladimir [108]

Answer:   (-1,3)

                (0,1)

               (1,-1)

              (2,-3)

Step-by-step explanation: For example, you put -1 as x in the equation, and then solve, your answer would be the y, and the number you inputted would be the x.

3 0
4 years ago
Consider that x = −5 and y = −4. Which statement is true about x + y?
ivanzaharov [21]

Answer:

The sum of x and y is a rational number.

Step-by-step explanation:

-5 + -4 = -9

-9 is a rational number

8 0
3 years ago
Divide. PLEASE HELP ME 312÷37
seraphim [82]

Answer:

since, hcf(312, 37) = 1

therefore, the answer will come in decimal form.

i.e., 8.4324324324

5 0
4 years ago
PLEASE HELP!
Nadya [2.5K]

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Step-by-step explanation:

8 0
3 years ago
Which is the polynomial function of lowest degree with rational real coefficients, a leading coefficient of 3 and roots StartRoo
spayn [35]

Answer:

f(x)=3x^3-6x^2-15x+30

Or

f(x)=3(x-2)(x+\sqrt{5})(x-\sqrt{5})

Step-by-step explanation:

For a polynomial function of lowest degree with rational real coefficients, each root has multiplicity of 1.

The polynomial has roots x=\sqrt{5} and 2 with a leading coefficient of 3.

By the irrational root theorem of polynomials, x=-\sqrt{5} is also a root of the required polynomial.

By the factor theorem, we can write the polynomial in factored form as:

f(x)=3(x-2)(x+\sqrt{5})(x-\sqrt{5})

We expand, applying difference of two squares to obtain

f(x)=3(x-2)(x^2-5)

We expand further using the distributive property to get:

f(x)=3x^3-6x^2-15x+30

3 0
4 years ago
Read 2 more answers
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