Ask question

Ask question

All categories

3 years ago

7

Your friend George is 6 feet tall and his shadow is 10 feet long. At the same time, the shadow of the flagpole was 85 feet long.

What is the height of a flagpole?
1.4 feet

60 feet

51 feet

141.6 feet

1 answer:

Leokris [45]3 years ago

8 0

Answer:

51 feet

Step-by-step explanation:

Let

x -----> the height of a flagpole

we know that

Using proportion

$\frac{6}{10}=\frac{x}{85} \\\\x=6*85/10\\\\x=51\ ft$

You might be interested in

1. Divide 6x^4 + 2x^3 – 6x^2 – 14x – 1 by 3x + 1 by using synthetic division or long division. Show all

iris [78.8K]

      2x^3 - 2x - 4

3x + 1 6x^4 + 2x^3 - 6x^2 - 14x - 1
      6x^4 + 2x^3

       -6x^2 - 14x - 1
   -6x^2 - 2x

   -12x - 1
   -12x - 4

   3

3x + 1 is not a factor of the dividend because, dividing the dividend with 3x + 1 gives a remainder.

5 0

3 years ago

Enter <,>,= to make the problem true -19 5/6 _ -20 1/6

NemiM [27]

Answer:

>

..................................................................

8 0

2 years ago

annie puts 10 dollars into a vacation jar each week.how much will she have saved by the ebd of the week

lubasha [3.4K]

Annie will have $70 because if you multiply 7 times 10 you get 70

5 0

2 years ago

Read 2 more answers

In triangle ABC, the side lengths are AB = 13, AC = 21, and BC = x. Write a compound inequality that represents the range of pos

N76 [4]

There is only 1 solution for the length of BC.

We can calculate it using Pythagorean theorem.

We can conclude that triangle's hypotenuse is AC.

$AC^2=AB^2+BC^2$

If that is the case we are looking for a side BC.

$BC=\sqrt{AC^2-AB^2}$

Now put in the data.

$BC=\sqrt{21^2-13^2}=\sqrt{272}=\sqrt{272}\approx\boxed{16.49}$

Hope this helps.

r3t40

7 0

3 years ago

Consider functions f and g

Alex

Answer:

1)D 2) Can't see the function

7 0

1 year ago