All categories

2 years ago

Help!!!!! PLease show all work!!

Mathematics

1 answer:

Sophie [7]2 years ago

8 0

I believe the answer is B because you have to do the Vertical Line Test.<span />

You might be interested in

A bicycle store costs $2700 per month to operate. The store pays an average of $65 per bike. The average selling price of each

vladimir2022 [97]

Answer:$90

Step-by-step explanation:

how much they sell for $95 minus how much they cost $65 equals $30 then divid how much rent is $2700 by the $30 equals $90

$95-$65=$30

$2700÷$30=90

7 0

2 years ago

Which set of side lengths create a right triangle ?

I am Lyosha [343]

Answer:

(8, 15 and 17)

Step-by-step explanation:

$\sqrt{10^{2} +28^{2} } \neq 29$

$\sqrt{6^{2} +8^{2} } \neq 13$

$\sqrt{7^{2} +12^{2} } \neq 14$

$\sqrt{8^{2} +15^{2} } =17$

3 0

2 years ago

Express the fractions 3/4 ,7/16 and 5/8 with the lowest common denominator

xxTIMURxx [149]

3/4, 7/16, 5/8.....LCD = 16

3/4 = 12/16
7/16
5/8 = 10/16

4 0

2 years ago

In analyzing the city and highway fuel efficiencies of many cars and trucks, the mean difference in fuel efficiencies for the 60

Olegator [25]

Answer:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

Step-by-step explanation:

Data provided

$\bar X=7.38$ represent the sample mean for the fuel efficiencies

$\mu$ population mean

s=2.51 represent the sample standard deviation

n=601 represent the sample size

Confidence interval

The formula for the confidence interval of the true mean is given by:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom for this case is given by:

$df=n-1=601-1=600$

The Confidence level for this case is 0.95 or 95%, and the significance level $\alpha=0.05$ and $\alpha/2 =0.025$ and the critical value is given by $t_{\alpha/2}=1.96$

Replcing into the formula for the confidence interval is given by:

$7.38-1.96\frac{2.51}{\sqrt{601}}=7.18$

$7.38+1.96\frac{2.51}{\sqrt{601}}=7.58$

For this case the confidence interval is given by :

$7.18 \leq \mu \leq 7.58$

8 0

3 years ago

Can anyone help me solve this please? I’m confused.

Varvara68 [4.7K]

From what is there it is nearly impossible to find an exact number so I would say C... hope this helps

7 0

2 years ago