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tatuchka [14]
3 years ago
8

Alisa says it is easier to compare the numbers in set a than in set b.

Mathematics
2 answers:
Sidana [21]3 years ago
8 0
I don't know vrghhhhhhhhhhhh
Oksana_A [137]3 years ago
7 0

Answer:

She can use the knowledge of place value to compare the numbers in set a than in set b.

Step-by-step explanation:

Consider the provided sets.

According to place value chart:

  Millions    Hundred Th.  Ten Th.    Thousands  hundreds Tens Ones

1,000,000     100,000      10,000       1000             100          10       1

Consider the set A) 45,760 & 1,025,680

In number 45,760 the first digit from left is 4 which is at ten thousands place.

In number 1,025,680 the first digit from left is 1 which is at million place.

So, it is easy to identify which number is greater by just seeing the greatest place value of the number.

Consider the set B. 492,111 & 409,867

Now consider the number 492,111 and 409,867

In number 492,111 the first digit from left is 4 which is at hundred thousands place.

In number 409,867 the first digit from left is 4 which also at hundred thousands place.

The greatest place value of both the number is same, so by seeing greatest place value number we can not identify which number is greater, to identify which number is greater we further need to compare the digit at ten thousands place.

Hence, by using the knowledge of place value she can compare the numbers in set a than in set b.

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If I put a different sticker on the 30th, 50th, and 60th pages will any of the first 600 pages have all 3 stickers?
icang [17]

Answer:

so the which page that will have the 3 sticker, we must solve the least common multiple of 30, 50, 60. A common multiple is a number that is a multiple of two or more numbers. The common multiples of 3 and 4 are 0, 12, 24, ....

The least common multiple (LCM) of two numbers is the smallest number (not zero) that is a multiple of both.

so the least common multiple of 30, 50 and 60 is 300. so the page that will have 3 stickers is 300th page

Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
Y = 15x <br> y = 25 + 12.5x
swat32

Substitute y = 15x to the equation y = 25 + 12.5x:

15x = 25 + 12.5x     <em>subtract 12.5x from both sides</em>

2.5x = 25    <em>divide both sides by 2.5</em>

x = 10

Substitute the value of x to the equation y = 15x:

y = (15)(10)

y = 150

<h3>Answer: x = 10 and y = 150</h3>
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saveliy_v [14]

Answer:

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Step-by-step explanation:

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