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Svetach [21]
3 years ago
5

A flea weighs 8 decigrams, and an ant weighs 3 milligrams. How much more does a flea weigh than an ant?

Mathematics
2 answers:
Flauer [41]3 years ago
8 0
1 decigram is 100 milligrams so the flea weighs 800 milligrams and 800-3=797 so the flea weighs 727 milligrams more than the ant
BlackZzzverrR [31]3 years ago
7 0
797
i hope it helped i did for me

You might be interested in
Rosa climbs a 16-meter tower to ride a straight water slide. After landing in the slash pool, she walks 9 meters back to the bas
erastova [34]

Answer:

The length of slide is 18.36 meters

Step-by-step explanation:

The given scenario forms a right-angled triangle where

The height of tower id perpendicular, the distance between slash pool and base of tower is base and the length of slide will be hypotenuse.

Height of tower = h = 16 meters

Distance between slash pool and base of tower = b = 9 meters

Length of slide = s = ?

As it is a right angled triangle, we can use Pythagoras theorem to find the length of slide

Pythagoras theorem states that:

(Hypotenuse)^2 = (Base)^2+(Perpendicular)^2\\s^2 = b^2+h^2\\s^2 = (9)^2+(16)^2\\s^2 = 81+256\\s^2 = 337\\s^2 = 18.36\ meters

Hence,

The length of slide is 18.36 meters

4 0
2 years ago
(02.09) Given a triangle with vertices at points (4, 4), (4, 1), and (2, 1), which set of ordered pairs represents the new verti
wel
Hello!

This triangle is currently located in Quadrant 1. If it is rotated 90 degrees counter-clockwise around the origin, it will end up in Quadrant 2. The formula for this is seen below.

(x,y)⇒(-y,x)

We will do this to each point and get our final points.

(4,4)⇒(-4,4)
(4,1)⇒(-1,4)
(2,1)⇒(-1,2)

Therefore, the final points of our rotated triangle are (-4,4), (-1,4) and (-1,2).

I hope this helps!


4 0
3 years ago
Factor the following expression using the GCF.
Jet001 [13]

Answer:

the answer to your question is 8r(d-3)

hope this helps :-)

3 0
2 years ago
A) how many ways are there to choose 10 players to take the field?
Kruka [31]

A. C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.C(13, 10) = 13! = 13·12·11 = 13 · 2 · 11 = 286.

B. P(13,10)= 13! =13! =13·12·11·10·9·8·7·6·5·4. (13−10)! 3!

C. f there is exactly one woman chosen, this is possible in C(10, 9)C(3, 1) =

10! 3!

9!1! 1!2! 10! 3!

8!2! 2!1! 10! 3!

7!3! 3!0!

= 10 · 3 = 30 ways; two women chosen — in C(10,8)C(3,2) =

= 45·3 = 135 ways; three women chosen — in C(10, 7)C(3, 3) =

= 10·9·8 ·1 = 120 ways. Altogether there are 30+135+120 = 285 1·2·3

<span>possible choices.</span><span> 
</span>

  


5 0
3 years ago
Solving systems equations: substitution <br> y=6x+5<br> y=4x+5
Andreas93 [3]
6x + 5 = 4x + 5
2x + 5 = 5
2x = 0, x = 0
Y = 6(0) + 5, y = 5
Solution: x = 0, y = 5
8 0
2 years ago
Read 2 more answers
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